Answer:
A. 12
Step-by-step explanation:
Selecting B, C, or D would create a difference of perfect squares since each of these numbers are perfect squares. Additional factoring would then be needed.
But selecting 12 gives which cannot be factored. It is factored completely.
The two expressions that represent the retail price of cars is: Retail price = 1.21c and Retail price = c + 0.21c
<em><u>Solution:</u></em>
Given that,
Rick buys remote control cars to resell
He applies a markup of 21%
Let "c" be the original price of remote control cars
To find: Expression for retail price of car
We know that,
Retail price = original price + markup
Here, markup price = 21 % of original price
Markup price = 21 % of c
Therefore, substituting the given values we get,
Retail price = c + 21 % of c
This can also be expressed as,
Thus two expressions that represent the retail price of cars is: Retail price = 1.21c and Retail price = c + 0.21c
Answer:
1. M=108
2. μ=110
3. In the explanation.
4. Test statistic t = -1.05
5. P-value = 0.1597
Step-by-step explanation:
The question is incomplete: to solve this problem, we need the sample information: size, mean and standard deviation.
We will assume a sample size of 10 matches, a sample mean of 108 points and a sample standard deviation of 6 points.
1. The mean points is the sample points and has a value of 108 points.
2. The null hypothesis is H0: μ=110, meaning that the mean score is not significantly less from 110 points.
3. This is a hypothesis test for the population mean.
The claim is that the mean score is significantly less than 110.
Then, the null and alternative hypothesis are:
The significance level is 0.05.
The sample has a size n=10.
The sample mean is M=108.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.
The estimated standard error of the mean is computed using the formula:
4. Then, we can calculate the t-statistic as:
The degrees of freedom for this sample size are:
5. This test is a left-tailed test, with 9 degrees of freedom and t=-1.05, so the P-value for this test is calculated as (using a t-table):
As the P-value (0.1597) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the mean score is significantly less than 110.