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3 years ago

15

What is 8172 divided by 9?

2 answers:

Lemur [1.5K]3 years ago

6 0

First we can solve 8100 by 9. Since we know 81/9=9, then 8100/9=900.
72/9=8

Now we can add them together 900+8=908.

The answer is 908.

kogti [31]3 years ago

4 0

8172/9=908 the answer is 908

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Nathan has three pieces of wood the first is 9.8 feet in length the second is 7.5 feet in length and the third is 12 feet in len

snow_tiger [21]

9.4 Ft for the first one

7.5 Ft for the second piece

12 Ft for the Third

he uses 5.2 Ft from the first piece of wood so 9.4 - 5.2= 4.6ft
he uses 6.1 ft from the second piece of wood , 7.5 - 6.1 = 1.4 ft
Nathan didnt use any of the 3rd piece of wood , so he still have 12 Feet of wood remaining so, 12+4.6+1.4 = 18 feet of wood left that he didnt use.

8 0

3 years ago

If v varies directly as w, and v=24 when w= 8, find the equation that relates v and w

Zigmanuir [339]

Answer:

v=3w

Step-by-step explanation:

v∝w

v=kw

24=8k

k=24/8 = 3

equation connecting v and w is

v=3w

5 0

3 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

Someone convert 58.6...... into a fraction thank you!

12345 [234]

586/10 -> 293/5 -> 58 3/5

4 0

2 years ago

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Jia spends $8 on 4 pounds of fruit. How much would he pay for one pound of fruit?

krek1111 [17]

Answer:

2 dollars

Step-by-step explanation:

For 4 pounds of fruit he pays 8 dollars. If you use the unit rate it is 2 dollars for every one pound of fruit

4 0

3 years ago

Read 2 more answers