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miv72 [106K]
4 years ago
7

Just two Algebra questions. Thank you :)

Mathematics
1 answer:
tekilochka [14]4 years ago
8 0
4m^6 - 16m^{10}

= (2m^3)^2 - (4p^5)^2

= (2m^3 -4p^5)(2m^3 + 4p^5)

================================
This expression is the difference of 2 squares :

\bf 9n^4 - 49n^6

= (3n^2)^2 - (7n^4)^2

= (3n^2 + 7n^4) (3n^2 - 7n^4)

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wariber [46]

Answer:

1- Circumference: 43.96 Area: 153.86

2- Circumference: 69.08  Area: 379.94

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5- Circumference: 57.78 Area: 265.77

3 0
2 years ago
Read 2 more answers
Please answer this correctly
Andreyy89

Answer: 1-20=2  and 60-80=4

Step-by-step explanation:

the first is 2 number of building

and the third one is 4 number of buldings

Hope this helps :)

7 0
4 years ago
Find the slope of the line shown in the figure
diamong [38]
It's undefined, but I think you spelled it wrong.
4 0
3 years ago
Read 2 more answers
Ram noticed three students used 1 2/10 dm of tape.what was the total used for three students???
OLga [1]

Answer:

18/5

Step-by-step explanation:

<em>From my understanding, this is 1 whole 2 upon 10</em>

<u>Step 1: Convert mixed fraction into fraction</u>

<em>Multiply whole number by denominator: 1 x 10 = 10</em>

<em>Add numerator: 10 + 2 = 12</em>

<em>Write the result as the numerator and use the same denominator.</em>

12/10

<u>Step 2: Find the total tape used</u>

<em>From my understanding, each student used 12/10 of the tap</em>

<em>So 3 students used: 12/10 x 3 =</em> 18/5

Therefore, the total tape used for three students was 18/5.

!!

7 0
3 years ago
2.The number of tickets sold to a play for each showing is 78, 84, 87, 80, 91, 95, and 80.
Luden [163]

Answer:

Min =78

The maximum is :

Max = 95

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

Median =84

Now we can find the quartile 1 we analyze the first 4 values  78, 80,80, 84 and the first quartile would be:

Q_1= \frac{80+80}{2}= 80

Now we can find the quartile 3 we analyze the last 4 values  84,87, 91, 95 and the third quartile would be:

Q_3= \frac{87+91}{2}=89

And finally the 5 number summary would be:

Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96

Step-by-step explanation:

We have the following data given:

78, 84, 87, 80, 91, 95, and 80.

The first step is order the dataset on increasing way and we got:

78, 80,80, 84,87, 91, 95

We can begin finding the minimum value and for this case is:

Min =78

The maximum is :

Max = 95

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

Median =84

Now we can find the quartile 1 we analyze the first 4 values  78, 80,80, 84 and the first quartile would be:

Q_1= \frac{80+80}{2}= 80

Now we can find the quartile 3 we analyze the last 4 values  84,87, 91, 95 and the third quartile would be:

Q_3= \frac{87+91}{2}=89

And finally the 5 number summary would be:

Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96

5 0
3 years ago
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