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miv72 [106K]
3 years ago
7

Just two Algebra questions. Thank you :)

Mathematics
1 answer:
tekilochka [14]3 years ago
8 0
4m^6 - 16m^{10}

= (2m^3)^2 - (4p^5)^2

= (2m^3 -4p^5)(2m^3 + 4p^5)

================================
This expression is the difference of 2 squares :

\bf 9n^4 - 49n^6

= (3n^2)^2 - (7n^4)^2

= (3n^2 + 7n^4) (3n^2 - 7n^4)

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Suppose that x and y vary inversely and that y = 5 when x = 1. What is y when x = 15?
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Answer:

Y=1/3

Step-by-step explanation:

X=k/y

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7 0
3 years ago
A college student Earned $6500 during summer vacation working as a waiter. The student invested Part of the money at 10% and the
Juliette [100K]

Answer:

The amount invested at 10% rate is $ 2200

Step-by-step explanation:

Given as :

The total amount earn by student = $6500

The total interest received at the end of year = $607

Let the amount invested at 10% rate = $x

So, The amount invested at 9% rate = ($6500 - $x)

Let the time for which money invested = 1 year

<u>Now from Simple Interest method :</u>

SI = \frac{principal\times Rate\times Time}{100}

Or, SI_1 + SI_2 = \frac{x\times 10\times 1}{100} + \frac{(6500-x)l\times 9\times 1}{100}

Or, SI_1 + SI_2 = (\frac{10x}{100})+\frac{(6500-x)\times 9}{100}

Or, $607 × 100 = 10x + (6500-x) × 9

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Hence The amount invested at 10% rate is $ 2200   Answer

5 0
3 years ago
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