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4 years ago

EASY 4 MOST PLZ HELP IM GONNA FAIL!!!!!(my grade is dropin) oof

Mathematics

2 answers:

Free_Kalibri [48]4 years ago

8 0

The answer is 0.375%

QveST [7]4 years ago

4 0

the answer is 37.5% sorry if im wrong

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SIZIF [17.4K]

Answer:

ti is m(B{AC=70*

Step-by-step explanation:

8 0

3 years ago

-7 times -8? -40 divided by 10?

alekssr [168]

-7 times -8 is 56 and -40 divided by 10 is -4

4 0

3 years ago

the mean sale per customer for 40 customers at a grocery store is $23.00, with a standard deviation of $6.00. Apply Chebyshev's

Lunna [17]

The answers is 75%x40=0.75x40=30

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3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPP

mixer [17]

Answer:

x = 20

Step-by-step explanation:

The angles shown are alternate exterior angles.

Alternate exterior angles are congruent

This means that 46 must equal 3x - 14

Note that we've just created an equation that we can use to solve for

We now use the equation to solve for x

3x - 14 = 46

add 14 to both sides

3x - 14 + 14 = 46 + 14

simplify

3x = 60

Divide both sides by 3

3x / 3 = x

60 / 3 = 20

We get that x = 20

4 0

3 years ago

Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil

andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that $p = 0.26$

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that $n = 5$

4 failures, so 1 success, and we have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898$

0.3898 = 38.98% probability that there will be 4 failures

4 0

3 years ago