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stiv31 [10]
3 years ago
15

What is the final concentration if a saline solution consisting of 20% NaCl is diluted using a 1/4 solution?

Mathematics
1 answer:
vodomira [7]3 years ago
6 0

Answer: C.V=C1.V1 +C2.V2

Step-by-step explanation: C=(C1V1 + C2V2)/V -> C=(20%.V+25%V)/2V-> C=22,5%

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A because it’s 3/4 away from the middle & up 2 so it’s gonna be half
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asambeis [7]

Answer:

  The sum of 2 and the quotient of 3 and y

Step-by-step explanation:

The expression 2 + 3/y without any parentheses is evaluated as ...

  2 + (3/y)

which is a sum. The first contributor to the sum is 2, and the second contributor is the quotient of 3 and y. (Usually, "the quotient of "a" and "b" means "a/b".)

Hence the answer shown above is a good description of the expression.

3 0
3 years ago
Gracie wants to buy a ring for her mom's birthday. But, the ring costs $897. Gracie only has $45. Her friend Jasmine tries do he
Leno4ka [110]

Answer:

$790.00

Step-by-step explanation:

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7 0
3 years ago
PLEASE HELP
Elza [17]

Answer:

$1.40

Step-by-step explanation:

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4 0
2 years ago
HELP PLS FOR BRAINLIEST!
igomit [66]

Answer:

Electric force = 8.20x10⁻⁸ N

Gravitational force = 3.61x10⁻⁴⁷ N

Step-by-step explanation:

1. The electric force can be found using the following equation:

F_{e} = \frac{Kq_{e}q_{p}}{d^{2}}

Where:

K: is the Coulomb's constant = 9x10⁹ N.m²/C²      

q_{p}: is the charge of the proton = 1.6x10⁻¹⁹ C

q_{e}: is the charge of the electron = -1.6x10⁻¹⁹ C

d: is the distance = 5.3x10⁻¹¹ m

Hence, the magnitude of the electric force is:

|F_{e}| = \frac{9\cdot 10^{9} N.m^{2}/C^{2}*(-1.6\cdot 10^{-19} C)*1.6 \cdot 10^{-19} C}{(5.3 \cdot 10^{-11} m)^{2}} = 8.20 \cdot 10^{-8} N                

2. The gravitational force can be calculated as follows:

F_{g} = \frac{Gm_{e}m_{p}}{d^{2}}

Where:

m_{e}: is the electron's mass = 9.1x10⁻³¹ kg

m_{p}: is the proton's mass = 1.67x10⁻²⁷ kg

G: is the gravitational constant = 6.67x10⁻¹¹ N.m²/kg²

Therefore, the gravitational force is:

F_{g} = \frac{6.67 \cdot 10^{-11} N.m^{2}/kg^{2}*9.1 \cdot 10^{-31} kg*1.67 \cdot 10^{-27} kg}{(5.3 \cdot 10^{-11} m)^{2}} = 3.61 \cdot 10^{-47} N

As we can see, the gravitational force is much less than the electric force.

I hope it helps you!                                                      

5 0
3 years ago
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