Let the amount deposited (principal) be x, then the amount after the required time = 2x.
A = P(1 + r/n)^nt: where A is the future value = 2x, P is the principal = x, r is the rate = 0.75%, n is the number of accumulation in a year = 12, t is the number of years.
2x = x(1 + 0.0075/12)^12t
2 = (1 + 0.000625)^12t
log 2 = 12t log (1.000625)
log 2 / log (1.000625) = 12t
1109.38 = 12t
t = 92 years
17.
x = -2 is not a solution of -1 < x < 5 because -2 < -1 (-1 < -2 < 5 FALSE).
18.
m = 5 is a solution of 5 ≤ m because 5 ≤ 5 ( 5 ≤ m → m ≥ 5 greater than 5 or equal 5, 5 is equal 5)
19.
k = 10 is not solution of 2k - 3 < 1 because:
put the value of k to the inequality:
2(10) - 3 < 1
20 - 3 < 1
17 < 1 FALSE
Chun wants to <span>reduce the weight of garbage produced to 85% of the weight produced this month.
This means that, Chun's garbage weight next month should be equal to 85% of his garbage weight this month.
Translating this into an equation, we will find that:
garbage weight next month = 85% of garbage weight this month
garbage weight next month = 0.85 * garbage weight this month
garbage weight next month = 0.85*690
garbage weight next month = 586.5 pounds
Based on the above calculations, his target weight for the garbage next month is </span>586.5 pounds
Answer:
Step-by-step explanation:
hello :
here is an solution
Answer:
the answer is c
Step-by-step explanation:
