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Sergio [31]
4 years ago
7

Find the equation of the line through the pair of points (1/2,1/8) and (-1/7,1/9)in standard form using only integers.

Mathematics
1 answer:
Effectus [21]4 years ago
3 0
The first thing that we need to do is find the slope (m). In order to find the slope we need two points. The first point is (x1,y1) and the second point is (x2,y2). The slope is m = (y2-y1)/(x2-x1) = (1/9 - 1/8)/(-1/7 - 1/2) = (8/72 - 9/72)/
(-2/14 - 7/14) = -(1/72)/(-9/14) = 1(14)/72(9) = 7/(36)(9) = 7/324 (Wow!)

Now we can use the point slope formula to make the equation:
y - 1/8 = (7/324)(x - 1/2)  Point slope equation
y - 1/8 = (7/324)x - 7/648
y =(7/324)x - 7/648 + 81/648
y = (7/324)x +74/648
y = (7/324)x + 37/324   This is the slope intercept form
-(7/324)x + y = 37/324  This is the standard form

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kotegsom [21]

Answer:

a, b

Explanation:

For a, pi is irrational.

For b, sqrt(24) is not a perfect square and therefore irrational.

For c and d, there are no irrational numbers.

If this helped please consider marking me brainliest.

7 0
4 years ago
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A parabolic microphone used on the sidelines of a professional football game uses a reflective dish 24 inches wide and 6 inches
Strike441 [17]
The answer is a.
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Then we go on to solve the equation by plugging in the numbers 12^2=4a(6)
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5 0
3 years ago
An expression is given.
lubasha [3.4K]

Answer:

19

Step-by-step explanation

8 0
3 years ago
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What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?
Natali5045456 [20]

Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

Step-by-step explanation:

Given:  

Let,  

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:  

Equation of Line  that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?  

Solution:  

x-6y=42    ..................Given

which can be written as

y=mx+c

Where m is the slope of the line

∴ y=\dfrac{x}{6}-7

On Comparing we get

Slope = m = \dfrac{1}{6}

The Required line is Perpendicular to the above line.

So,

Product of slopes = - 1

m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

(y-y_{1})=m(x-x_{1})

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

3 0
3 years ago
Each side of a sugar cube is 0.6 in long. what is the volume of each sugar cube
cestrela7 [59]
Volume of a cube is expressed by: V = a^3
So a = 0.6
V = (0.6)^2
V = 0.22 approx.

Hope this Helps! :)
8 0
3 years ago
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