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Sergio [31]
3 years ago
7

Find the equation of the line through the pair of points (1/2,1/8) and (-1/7,1/9)in standard form using only integers.

Mathematics
1 answer:
Effectus [21]3 years ago
3 0
The first thing that we need to do is find the slope (m). In order to find the slope we need two points. The first point is (x1,y1) and the second point is (x2,y2). The slope is m = (y2-y1)/(x2-x1) = (1/9 - 1/8)/(-1/7 - 1/2) = (8/72 - 9/72)/
(-2/14 - 7/14) = -(1/72)/(-9/14) = 1(14)/72(9) = 7/(36)(9) = 7/324 (Wow!)

Now we can use the point slope formula to make the equation:
y - 1/8 = (7/324)(x - 1/2)  Point slope equation
y - 1/8 = (7/324)x - 7/648
y =(7/324)x - 7/648 + 81/648
y = (7/324)x +74/648
y = (7/324)x + 37/324   This is the slope intercept form
-(7/324)x + y = 37/324  This is the standard form

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Answer:

The correct quotient is 3.

I think Derek has mistaken to divide -\frac{2}{21} by \frac{2}{7}.

Step-by-step explanation:

We have to check the quotient of (-\frac{2}{7})  \textrm{ divided by }(-\frac{2}{21}).

Part A:

Now, (-\frac{2}{7})  \textrm{ divided by }(-\frac{2}{21}).

= \frac{-\frac{2}{7} }{-\frac{2}{21} } =3

So, the correct quotient is 3.

Part B:

Derek says that the quotient is -\frac{1}{3}.  

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