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3 years ago

What is the mid point of AB

Mathematics

1 answer:

enot [183]3 years ago

3 0

Answer:

There's no specific answer

Step-by-step explanation:

If you want the Midpoint M between A and B then you should use the equation $\frac{A + B}{2}$

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Inessa [10]

The answer is -19 1/2 feet

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3 years ago

12 liters is about how many quarts

pashok25 [27]

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3 years ago

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maxonik [38]

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3 years ago

Without a calculator how would you solve this?

mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

$\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6$

$=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}$

$\bigstar\ (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}$

$\bigstar\ \bigstar\ (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}$

$\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702$

$\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6$

$0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0$

$\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0$

$\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702$

8 0

2 years ago

In right triangle ABC, C is the right angle. Which of the following is cos B if sin A = 0.4

inessss [21]

Answer:

Given that,

In right triangle ABC, C is the right angle.

sin A=0.4

To find cos B,

we get the triangle as,

we know that,

Hypotenuse of the triangle is AB

For the angle A, opposite side is CB

For the angle B, adjacent side is CB

From the definition of sine and cosine we get,

$\sin A=\frac{CB}{AB}$

Also,

$\cos B=\frac{CB}{AB}$

Comparing both we get,

$\sin A=\cos B$

It is given that sinA=0.4

Hence we get, cosB=0.4

Answer is: 0.4

7 0

1 year ago