<h3>
Answer:</h3>
C) y = 6x
<h3>
Step-by-step explanation:</h3>
Pick any point. It is often convenient to use x = 1 (no marked point) or x = 10 (where y = 60).
Use these values to see which equation agrees.
A: 60 ≠ (1/6)·10
B: 60 ≠ 2·20
C: 60 = 6·10
D: 60 ≠ 12·10
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Or, you can solve ...
... y = kx
for k, using the point values you found on the graph.
... 60 = k·10
... 60/10 = k = 6 . . . . . divide by 10
This makes the equation be ...
... y = 6x . . . . . . matches selection C
Starting with x=1, subtract 1 from each side,
(x-1)=0
Our polynomial will have multiplicity of 2 for this particular zero,
(x-1)(x-1)
and do similar with the x=-4, add 4 to each side,
(x+4)=0
So our final result is: (x-1)(x-1)(x+4)
Expand out the brackets if you need this in standard form.
The shaded area is 299.59un^2.
Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8
Answer:
Your answer should be AC=2DF=34
Step-by-step explanation:
