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3 years ago

Find the range of the following data. Scores:81,79,80,88,72,96,86,73,79,88

Mathematics

1 answer:

kumpel [21]3 years ago

5 0

Answer:

Step-by-step explanation:

Range is subtracting the lowest number with the highest therefore 72-96 and you will get 24

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What is 46785392+78 ?

worty [1.4K]

The answer is 46,785,470

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3 years ago

Read 2 more answers

Determine the equation of the line passing through the points <br> (4,-1) and (-2,-4)

jenyasd209 [6]

Answer:

y = 1/2x - 3

Step-by-step explanation:

the slope:

$m=\frac{-4-(-1)}{-2-4} =\frac{-4+1}{-6} =\frac{-3}{-6} =\frac{3}{6} =\frac{1}{2}$

the equation:

with the point (4, -1)

$y-(-1)=\frac{1}{2} (x-4)$

$y+1=\frac{1}{2}x-2$

$y=\frac{1}{2} x-2-1$

$y=\frac{1}{2} x-3$

I hope this help you

8 0

3 years ago

HELP!!! Does the graph represent a function and if so, why? No, some of the ordered pairs in this list have the same second elem

vlabodo [156]

Answer:

No, some of the ordered pair in this graph have the same first element.

Step-by-step explanation:

The relation of a function is that it expresses a dependence of one element on another. There is a one to one relation, which means that one point can not be used more then once.

Some ordered pairs in this graph have the same first element and are used more then once. So this graph can not represent a function.

3 0

3 years ago

In 2002, there were 972 students enrolled at Oakview High School. Since then, the number of students has increased by 1.5% each

Rudiy27

Answer:

$N(t) = 972(1.015)^{t}$

Growth function.

The number of students enrolled in 2014 is 1162.

Step-by-step explanation:

The number of students in the school in t years after 2002 can be modeled by the following function:

$N(t) = N(0)(1+r)^{t}$

In which N(0) is the number of students in 2002 and r is the rate of change.

If 1+r>1, the function is a growth function.

If 1-r<1, the function is a decay function.

In 2002, there were 972 students enrolled at Oakview High School.

This means that $N(0) = 972$

Since then, the number of students has increased by 1.5% each year.

Increase, so r is positive. This means that $r = 0.015$

Then

$N(t) = N(0)(1+r)^{t}$

$N(t) = 972(1+0.015)^{t}$

$N(t) = 972(1.015)^{t}$

Growth function.

Find the number of students enrolled in 2014.

2014 is 2014-2002 = 12 years after 2002, so this is N(12).

$N(t) = 972(1.015)^{t}$

$N(12) = 972(1.015)^{12}$

$N(12) = 1162$

The number of students enrolled in 2014 is 1162.

7 0

3 years ago

Helppp more points 20 math

Serjik [45]

Answer:

root(250)

answer choice C

Step-by-step explanation:

explanation in the pic above.

7 0

3 years ago