Hi there!

We can see this by writing the factors as multipliers. We get the following:


Now we can see that the terms that are in common are 3 and a, and therefore we can bring those outside the parenthesis.
A.
F(10)= (10)^2-3(10)-5
F(10)=100-30-5
F(10)=65
B.
F(-3)=(-3)^2-3(-3)-5
F(-3)=9+9-5
F(-3)=13
C.
G(2)= -6(2)+1
G(2)= -12+1
G(2)=-11
D.
G(10)=-6(10)+1
G(10)= -60+1
G(10)= -59
Answer:
P=41.72
Step-by-step explanation:
S=ACxDB/2
81.7=8.6xDB/2
81.7=4.3xDB|:4.3
19(mm)=DB
DO=19/2=9.5
OC=8.6/2=4.3
(O is the center of the rhombus, where two diagonals meet)
a²+b²=c² (DO²+OC²=DC²)
9.5²+4.3²=c²
90.25+18,49=c²
√108,74=√c²
c≈10.43
P=4c
P=4x10.43
P=41.72
Hope it helps:)
Answer:
Point D
Step-by-step explanation:
To draw a perpendicular bisector between BE, you have take more than half of the length BE on the compass. So, it should be D