1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
Find the values of x in which ((mod (x))/mod(x-1)))+(mod (x))=(mod(x2))/(mod(x-1))
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i send u a picture of how i solve it. i hope this can help u
