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Delvig [45]
3 years ago
6

2/3(x+12)+2/3x=4 Solve the equation.

Mathematics
2 answers:
irga5000 [103]3 years ago
8 0
Simplify each term<span>.
</span><span><span><span>2x/</span>3</span>+8+<span><span>2x/</span>3</span>=4

</span>Add <span><span>2x/</span>3</span><span> and </span><span><span>2x/</span>3</span><span> to get </span><span><span>2(<span><span>2x/</span>3</span>)</span>.
</span>2(<span><span>2x/</span>3</span>)+8=<span>4
</span>
<span>Simplify.
</span><span><span><span>4x/</span>3</span>+8=4

</span>Since 8<span> does not contain the </span>variable<span> to solve for, move it to the right-hand side of the </span>equation<span> by subtracting </span>8<span> from both sides.
</span><span><span><span>4x/</span>3</span>=−8+4

</span>Add <span>−8</span><span> and </span>4<span> to get </span><span><span>−4</span>.
</span><span><span><span>4x/</span>3</span>=−4

</span>Multiply<span> both sides of the </span>equation<span> by </span><span>3.
</span><span>4x=−4⋅(3)

</span>Multiply <span>−4</span><span> by </span>3<span> to get </span><span><span>−12</span>.
</span><span>4x=−12

</span>Divide<span> each </span>term<span> in the </span>equation<span> by </span><span>4.
</span>x=−<span>3
</span>
x is equal to -3
andreyandreev [35.5K]3 years ago
3 0
2/3X + 8 +2/3X = 4
4/3X + 8 = 4
4/3X = -4
X = -12/4 = -3  
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Answer:

  • domain: {x ∈ ℝ : x ≤ 5}
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Step-by-step explanation:

<u>Domain</u>

The domain of a function is the set of x values for which the function is defined. Here, the domain is limited by the values of x that make the square root defined. That is, the expression under the radical cannot be negative:

  -3x +15 ≥ 0

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  domain: {x ∈ ℝ : x ≤ 5} . . . . . . matches the first choice

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<u>Range</u>

The range of a function is the set of values that f(x) can have. We know the square root can be zero or any positive number. When it is zero, f(x) = -1.

When it is a positive number, that value is multiplied by -4 and added to -1, so f(x) is a number more negative than -1. Then the range of the function is all numbers -1 and below:

  range: {y ∈ ℝ : y ≤ -1} . . . . . . matches the last choice

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<em>Comment on domain/range problems</em>

When working domain and range problems, it works well to have a good understanding of the domain and range limitations of the functions we usually work with: polynomials, square root, logarithm, trig functions, exponential functions. Domain and range problems generally involve combinations of these or ratios of combinations of these.

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