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3 years ago

8

Bruce evaluates the expression on a math quiz, 8.8 ÷ 2.7 and gets an answer of 4.14.

2 answers:

jolli1 [7]3 years ago

6 0

Answer:

the answer is D

Step-by-step explanation:

ella [17]3 years ago

4 0

The correct answer is choice d.....

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When Jorge put the pots and pans in the sink,the water level in the sink rose 0.6 inches. If the sink is a rectangular prism wit

Viktor [21]

$V_1$ - volume without <span>pots and pans
$V_2$ - volume with </span>pots and pans
$V_2-V_1$ - volume of pots and pans

$V_1=17\cdot23\cdot h=391h\ in^3\\ V_2=391(h+0.6)=391h+234.6\ in^3\\
V_2-V_1=391h+234.6-391h\\
V_2-V_1=234.6 \ in ^3$

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3 years ago

Pls help me with my math

xxTIMURxx [149]

Answer:a

Step-by-step explanation:Bottom line includes the end point so should be less than or equal. Top line does not so should be greater than

4 0

2 years ago

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katrin [286]

Answer:

i think its A but im not sure

4 0

3 years ago

Read 2 more answers

You can eliminate one of the variable terms in an ___ by adding or subtracting another equation

MakcuM [25]

Answer:

system of equations

Step-by-step explanation:

You can eliminate one of the variable terms in a <u>system of equations</u> by adding or subtracting another equation.

8 0

2 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

3 years ago