Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.
Using the binomial distribution, we want all three to be defective.


5x -3 = 12
5x -3 + 3 = 12 + 3 [Add 3 to each side]
5x + 0 = 15 [Evaluate]
5x/5 = 15/5 [Divide each side by 5]
1x = 3 [Evaluate]
The answer I get is the number 3.
Answer:
1) 36
b) 5
c) 3.0
Step-by-step explanation:
1) The recursive formula that defines the given sequence is

That means we keep adding 4 to the subsequent terms:
The sequence will be:
12,16,20,24,28,32,36,...
Therefore the seventh term is 36.
2) The sequence is recursively defined by;

This means, we have to keep subtracting 5 from the subsequent terms.
The sequence will be;
20,15,10,5,...
Therefore the fourth term is 5
3) The sequence is recursively defined by:
f(n+1)=f(n)+0.5
where f(1)=-1.5
This means that, the subsequent terms can be found by adding 0.5 to the previous terms.
The sequence will be:
-1.5,-1.0,-0.5,0,0.5,1,1.5,2.0,2.5,3.0,....
Therefore f(10)=3.0
Answer:
1: true
2: false
Step-by-step explanation:
1: congruent = equal while supplementary = 180-degrees
2: congruent angles= vertical angles, corresponding angles, alternate interior angles, & alternate exterior angles