What is the value of 9/10÷1/5 ?

Mathematics

2 answers:

Hoochie [10]3 years ago

6 0

Answer: 9/2

Step-by-step explanation:

Anna35 [415]3 years ago

3 0

The answer of 9/10 divided by 1/5 is 4.5

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Need Help With this question

Sidana [21]

Answer:

Area of ΔDEF = 12 in²

Step-by-step explanation:

Since they are similar, we have to find the scale factor

Scale Factor = $\frac{Side OfDilated Triangle}{Side of Original Triangle}$

Scale Factor = 4/2

Scale Factor = 2

This means The area of ΔABC is 2 times the area of ΔDEF

So,

ΔABC = 2(ΔDEF)

Where Area of ΔABC = 24 in²

24 = 2(ΔDEF)

Dividing both sides by 2

=> Area of ΔDEF = 12 in²

4 0

3 years ago

What Is the answer to 10ac-x/11=-3

cestrela7 [59]

Multiplty both sides by 11. 11 times 11 cancels out, 11 times -3 equals -33. You should get 10ac - x = -33
Add x to both sides: 10 a c = x − 33
Divide both sides by 10 c : a = x − 33 /10c

revised tada!

4 0

3 years ago

Rationalize the denominator and simplify. StartFraction 5 minus StartRoot 3 EndRoot Over 4 plus 2 StartRoot 3 EndRoot EndFractio

nasty-shy [4]

Answer:

$\frac{13-7\sqrt{3}}{2}$

Step-by-step explanation:

We need to rationalize the denominator of $= \frac{5-\sqrt{3}}{4+2\sqrt{3}}$ . For rationalizing we multiply the equation by $\frac{4-2\sqrt{3}}{4-2\sqrt{3}}$

So, solving

$= \frac{5-\sqrt{3}}{4+2\sqrt{3}}*\frac{4-2\sqrt{3}}{4-2\sqrt{3}} \\=\frac{(5-\sqrt{3})(4-2\sqrt{3})}{4+2\sqrt{3}*4-2\sqrt{3}}\\=\frac{(5-\sqrt{3})(4-2\sqrt{3})}{(4)^2-(2\sqrt{3})^2}\\= \frac{5(4-2\sqrt{3})-\sqrt{3}(4-2\sqrt{3})}{16-(4*3)}\\=\frac{20-10\sqrt{3}-4\sqrt{3}+2*3}{16-12}\\=\frac{20+6-14\sqrt{3}}{4}\\=\frac{26-14\sqrt{3}}{4}\\= \frac{2(13-7\sqrt{3})}{4}\\=\frac{13-7\sqrt{3}}{2}$