Let the number be x
(3/7) x = t
I can't think of anything useful to add to this. How about an example?

Let x = 49

(3/7) x = t
(3/7) * 49 = t seven will go into 49
3 * 49 = t
t = 147

8 0

3 years ago

Select the correct expressions. 1 Identify each expression that represents the slope of a tangent to the curve y= * +1 at any po

Olegator [25]

The expressions which represents the slope of a tangent to the curve $y=\frac{1}{x+1}$ at any point (x, y) are:

$f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}$

<h3>The slope of a tangent to the curve.</h3>

Mathematically, the slope of a tangent line to the curve is given by this equation:

$f'(x) =limh \rightarrow 0\frac{f(x+h)-f(x)}{h}$

Given the function:

$f(x)=y=\frac{1}{x+1}$

When (x + h), we have:

$f(x+h)=y=\frac{1}{x+h+1}$

Next, we would find the derivative of f(x):

$f'(x) =limh \rightarrow 0\frac{\frac{1}{x+h+1} -\frac{1}{x+1}}{h}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -(x+h+1)}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -x-h-1}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}\\\\f'(x) = \frac{-1}{(x+1)(x+1)} \\\\f'(x) = \frac{-1}{(x+1)^2}$

Read more on slope of a tangent here: brainly.com/question/26015157

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5 0

2 years ago

Find the value of the trig functions indicated .

lara31 [8.8K]

Answer:

The choice; B) 5/3

Step-by-step explanation:

${a}^{2} + {b}^{2} = {c}^{2} \\ {15}^{2} + {20}^{2} = {c}^{2} \\ 225 + 400 = {c}^{2} \\ {c}^{2} = 625 \\ c = 25$

$\sec(θ) = \frac{1}{ \cos(θ) } \\ \\ \sec(θ) = \frac{1}{ \frac{adjacent}{hypotenuse} } = \frac{hypotenuse}{adjacent} \\ \\ \sec(θ) = \frac{25}{15} = \frac{25 \div 5}{15\div 5} = \frac{5}{3}$

4 0

1 year ago

Suppose three out of every five people said they would prefer a television over a computer. If we surveyed 5,000 people, how man

Salsk061 [2.6K]

3/5 people means 60% prefer televisions.
60% of 5000 is equal to 0.6*5000=3000
Final answer: D

7 0

3 years ago

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