Answer:
No
Steps- two rang values exist for domain value -2
Let us say that:
x = the number of T shirts bought = 4
y = the number of leather jackets bought = 1
a = the price of the T shirts
b = the price of the leather jackets
With the given variables, we can say that the total cost
is:
total cost = a x + b y
Since, b = 6 a, therefore:
total cost = a x + 6 a y
total cost = a (x + 6 y)
Since total cost is 209, therefore we can calculate for a
since x and y are also given:
209 = a (4 + 6 * 1)
209 = a (10)
a = $20.9
<span>Therefore each T shirt cost $20.9</span>
Answer:
f(g(x)) = x^4 + 12x^3 + 14x^2 -132x + 123
Step-by-step explanation:
Here, we simply will place g(x) into f(x)
So every x in f(x) is replaced by g(x)
Thus, we have;
(x^2 + 6x + 11)^2 + 2
= (x^2+6x-11)(x^2 + 6x -11) + 2
= x^4 + 6x^3 -11x^2 + 6x^3 + 36x^2 - 66x -11x^2 -66x + 121 + 2
= x^4 + 12x^3 + 14x^2 -132x + 123
If you would like to know if 44 * 20 * 10 equals to 440 * 2, you can check it like this:
44 * 20 * 10 = 440 * 20 = 8800
and
440 * 2 = 880
So, the correct result is False, because 8800 is not equal to 880.
The awenser of the problem is A
