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Cloud [144]
3 years ago
12

a 5 miles race is approximately 8.05km . John is going to run a 5km race this Saturday. how many miles will he run ( round to th

e nearest tenth.
Mathematics
1 answer:
bonufazy [111]3 years ago
6 0
He will run about 3.1 miles
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Jen has three bracelets each bracelet has seven diamonds how many diamonds does Jen have in all 
konstantin123 [22]

Answer:

21 diamonds.

Step-by-step explanation:

1 bracelet = 7 diamonds

3 bracelet= ? diamonds

All we have to do is multiply 3 by 7 to get the number of diamonds Jen have with three bracelets.

3 x 7 = 21

7 0
3 years ago
Read 2 more answers
-17/30 write a fraction as a decimal
Whitepunk [10]
As a decimal the answer would be −0.566666666666667
7 0
3 years ago
The per capita electric power consumption level in a recent year in Ecuador is normally distributed, with a mean of 471.5 kilo-w
Olin [163]

Answer:

a) 471.5 kilo-watt hours.

b) 31.76 kilo-watt hours

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the population:

Mean 471.5 kilo-watt hours.

Standard deviation of 187.9 kilowatt-hours.

For the sample:

Sample size of 35, by the Central Limit Theorem:

a) Mean

471.5 kilo-watt hours.

b) Standard deviation

s = \frac{187.9}{\sqrt{35}} = 31.76

31.76 kilo-watt hours

7 0
3 years ago
a) A large hotel in Miami has 900 rooms (all rooms are equivalent). During Christmas, the hotel is usually fully booked. However
Olegator [25]

Answer:

14.69% probability that this happens

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

1000 people were given assurance of a room.

This means that n = 1000

Let us assume that each customer cancels their reservation with a probability of 0.1.

So 0.9 probability that they still keep their booking, which means that p = 0.9

Probability more than 900 still keeps their booking:

n = 1000, p = 0.9

So

\mu = 0.9, s = \sqrt{\frac{0.9*0.1}{1000}} = 0.0095

901/1000 = 0.91

So this is 1 subtracted by the pvalue of Z when X = 0.91.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{0.91 - 0.9}{0.0095}

Z = 1.05

Z = 1.05 has a pvalue of 0.8531

1 - 0.8531 = 0.1469

14.69% probability that this happens

3 0
3 years ago
I purchase x movie tickets y candy bars and z fountain drinks if each movie cost $11.50 each candy bar costs $2.25 and each foun
ANEK [815]

Answer:

t = 11.5 \times x + 2.25 \times y + 4.75 \times z

6 0
3 years ago
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