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2 years ago

Can someone help me find m

Mathematics

2 answers:

enyata [817]2 years ago

7 0

Answer:

m < LKH = 69°

Step-by-step explanation:

Given that m < LKM = 111° and that:

<LKM and <LKH are adjacent angles as they share the same vertex, point K, and same ray between them, KL:

Then we can assume that m < LKM and m < LKH are supplementary angles whose sum = 180°.

Therefore, we can establish the following equation:

m < LKM + m < LKH = 180°

111° + m <LKH = 180°

Subtract 111° from both sides to solve for m < LKH:

111° - 111° + m <LKH = 180° - 111°

m < LKH = 69°

Therefore, the measure of < LKH is 69°.

Please mark my answers as the Brainliest if you find my explanations helpful :)

Arturiano [62]2 years ago

6 0

Answer:

69 degrees

Step-by-step explanation:

m is a point, if your trying to find lkh, is 69

lkm=111, and jkl=180, so 180-111=jkm

jkm=69

angles that are diagonal from each other are the same degree

lkh=69

hope this helps, if not see me in the commnets

HOPE THIS HELPS, BRAINLIEST PLEASE

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Rufina [12.5K]

Answer:

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Step-by-step explanation:

We know that the sample size was:

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$\s = 345$

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The confidence interval for the mean is:

${\displaystyle{\overline {x}}} \± Z_{\frac{\alpha}{2}}*\frac{s}{\sqrt{n}}$

Looking at the normal table we have to

$Z_{\frac{\alpha}{2}}=Z_{\frac{0.01}{2}}=Z_{0.005}=2.576$

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$(1024.69,\ 1127.31)$

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3 years ago

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geniusboy [140]

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3 years ago

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balu736 [363]

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Solution:

Given expression is:

$1\frac{5}{7} \div \frac{4}{9}$

First let us convert the mixed fraction to improper fraction

Multiply the whole number by the denominator.

Add the answer from Step 1 to the numerator.

Write answer from Step 2 over the denominator.

Thus we get,

$1\frac{5}{7} = \frac{1 \times 7 + 5}{7} = \frac{12}{7}$

Now the given expression becomes,

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Convert the problem to multiplication by changing the division sign to multiplication and inverting the fraction to the right of the sign

$\frac{12}{7} \div \frac{4}{9} = \frac{12}{7} \times \frac{9}{4}$

Multiply the numerators, multiply the denominators, and leave the product in factored form

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