All categories

3 years ago

Can someone help me find m

Mathematics

2 answers:

enyata [817]3 years ago

7 0

Answer:

m < LKH = 69°

Step-by-step explanation:

Given that m < LKM = 111° and that:

<LKM and <LKH are <em><u>adjacent angles</u></em> as they share the same vertex, point K, and same ray between them, KL:

Then we can assume that m < LKM and m < LKH are supplementary angles whose sum = 180°.

Therefore, we can establish the following equation:

m < LKM + m < LKH = 180°

111° + m <LKH = 180°

Subtract 111° from both sides to solve for m < LKH:

111° - 111° + m <LKH = 180° - 111°

m < LKH = 69°

Therefore, the measure of < LKH is 69°.

Please mark my answers as the Brainliest if you find my explanations helpful :)

Arturiano [62]3 years ago

6 0

Answer:

69 degrees

Step-by-step explanation:

m is a point, if your trying to find lkh, is 69

lkm=111, and jkl=180, so 180-111=jkm

jkm=69

angles that are diagonal from each other are the same degree

lkh=69

hope this helps, if not see me in the commnets

HOPE THIS HELPS, BRAINLIEST PLEASE

You might be interested in

A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an

Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

$\tan\theta=\frac{perpendicular}{base}$

Here $\theta=45^{\circ}$ , perpendicular = 30 m and base we can find.

thus,

$\tan 45^{\circ}=\frac{30}{EA}$

We know $\tan 45^{\circ}=1$

thus, EA = 30 m

Consider the Δ AEB,

Using trigonometric ratio,

$\cos\theta=\frac{base}{hypotenuse}$

Here $\theta=60^{\circ}$ , hypotenuse = 80 m and base we can find.

thus, $\cos 60^{\circ}=\frac{base}{80}$

We know, $\cos 60^{\circ}=\frac{1}{2}$

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!

Y_Kistochka [10]

53 and 17

Step-by-step explanation:

If you add 53 and 17, you get 70.

If you subtract 17 from 53, you get 36. Hope this helps!

7 0

3 years ago

Five less than the product of 3 and a number of 40 . Write in an equation

vagabundo [1.1K]

Answer:

I don't get the "number of 40" part, but here's my best shot!

3(40x)-5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

nalin [4]

Answer:

No similarity and no scale factor (I could be wrong)

Step-by-step explanation:

Don't worry, no links :)

You would see if they are similar if they have similar sides. so if there is an equal ratio, to both, they are similar. Sometimes they may not look similar until you rotate them. So for the following, you can see that if E were on the bottom, it would look like the triangle with N and M on the bottom you can ensure this to look at the ratios of each side. To find the scale factor, it depends on which way you are going. are you going from GEF to MNL or MNL to GEF? To me, it doesn't look like there is a scale factor, but I could be wrong.

8 0

3 years ago

Solve for U -8u = - 16/3

lorasvet [3.4K]

Answer:

u = 2/3

Step-by-step explanation:

Simply divide both sides by -8:

u = (-16/3)/-8

If you don't have a calc, use KCF:

u = (-16/3)(-1/8)

u = 16/24

u = 2/3

4 0

3 years ago