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Andrew [12]
3 years ago
15

How do you write 20,484,163 in expanded form?for 5 grade

Mathematics
2 answers:
Setler [38]3 years ago
8 0
20,484, 163 = 2x10,000,000 + 4x100,000 + 8x10,000 + 4x1,000 +1x100 +6x10 +3x1

Hope this helps :P
Sav [38]3 years ago
6 0

Answer:

20,000,000 + 0 + 400,000 + 80,000 + 4,000 + 100 + 60 + 3 = 20,484,163

Step-by-step explanation:

The expanded form of a number is when a nukber is ex´panded to show the value of each digit. The number gets divided in ones, tens, hundreds, etc. depending on the amount of digits.

In this case:

20,000,000 - ten millions

0 - millions

400,000 - hundred thousands

80,000 - ten thousands

4,000 - thousands

100 - hundreds

60 - tens

3 - ones

The addition of all these numbers gives us the initial number.

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Simplify write equivalent expressions. 4-2+(3b+6)
Maksim231197 [3]
The first thing you want to do in this equation is get rid of the parenthesis. Because 4-2 is added to (3b+6) you cannot distribute the 2. However, there is an invisible 1 next to the parenthesis, so you can use that. Additionally, I like to change subtraction to addition of a negative number. It makes things a little less confusing.

4+ -2 + 3b + 6

Now just combine the like terms.

4 + -2 = 2
6+ 2 = 8

So the simplified version of your problem is: 3b + 8
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Answer:

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A lighthouse is located on an island 33 miles from the closest point on a straight shoreline. If the lighthouse light rotates cl
Zinaida [17]

Question:

A lighthouse is located on an island 3 miles from the closest point on a straight shoreline. If the lighthouse light rotates clockwise at a constant rate of 9 revolutions per minute, how fast does the beam of light move towards the point on the shore closest to the island when it is 52 miles from that point

Answer:

The beam of light moves at 16278\pi miles/min

Step-by-step explanation:

This question is illustrated with the attached image

Taking the instructions in the question, one at a time.

A revolution of 9 per minute implies that:

\frac{d\theta}{dt} = \frac{9 * 2\pi\ rad}{1\ min}

\frac{d\theta}{dt} = 18\pi \frac{rad}{min}

Take tan of the angle in the attachment:

tan(\theta) =\frac{52}{3}

Differentiate both sides with respect to time

\frac{d\ tan(\theta)}{dt} =\frac{52}{3} * \frac{dx}{dt}

Rewrite as:

\frac{d\ tan(\theta)}{d\theta} * \frac{d\theta}{dt} =\frac{52}{3} * \frac{dx}{dt}

In calculus:

sec^2(\theta) =\frac{d\ tan(\theta)}{d\theta} -- Chain rule

So:

sec^2(\theta) *\frac{d\theta}{dt} =\frac{52}{3} * \frac{dx}{dt}

In trigonometry:

sec^2(\theta) = tan^2(\theta) + 1

So:

(tan^2(\theta) + 1)\frac{d\theta}{dt} =\frac{52}{3} * \frac{dx}{dt}

Recall that:

tan(\theta) =\frac{x}{3}

((\frac{52}{3})^2 + 1)\frac{d\theta}{dt} =\frac{1}{3} * \frac{dx}{dt}

(\frac{52^2}{9} + 1)\frac{d\theta}{dt} =\frac{1}{3} * \frac{dx}{dt}

(\frac{2704}{9} + 1)\frac{d\theta}{dt} =\frac{1}{3} * \frac{dx}{dt}

(\frac{2704+9}{9})\frac{d\theta}{dt} =\frac{1}{3} * \frac{dx}{dt}

(\frac{2713}{9})\frac{d\theta}{dt} =\frac{1}{3} * \frac{dx}{dt}

Recall that: \frac{d\theta}{dt} = 18\pi \frac{rad}{min}

(\frac{2713}{9}) * 18\pi =\frac{1}{3} * \frac{dx}{dt}

2713 * 2\pi =\frac{1}{3} * \frac{dx}{dt}

Multiply both sides by 3

3 * 2713 * 2\pi =\frac{1}{3} * \frac{dx}{dt} * 3

3 * 2713 * 2\pi =\frac{dx}{dt}

16278\pi =\frac{dx}{dt}

\frac{dx}{dt} = 16278\pi miles/min

Hence:

The beam of light moves at 16278\pi miles/min

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Answer:$600

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