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Pie
3 years ago
5

The kindergarten teacher wants to divide 1/2 of her classroom into 5 equal sections for stations

Mathematics
2 answers:
weqwewe [10]3 years ago
8 0
Well do you have the amount of students in her class?  
mr Goodwill [35]3 years ago
8 0
There has to be more clues or factors to this question for it to be answered correctly.
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Factor the quadratic expression. x2 + 16x + 48
Bingel [31]
I will do my best to explain this “ x method “ I use
Basically, two factors of the first and last number must multiply together to sum up to equal the middle number
1 X 12
1 4
(x+12) (x+4)
Hope this helps!
3 0
3 years ago
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Help me PLEASEEEE<br> find the the angles
wel
You need to find x so that then you can do it and you didn’t share a answer so how are we supposed to know??
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3 years ago
A group of friends went to a sporting event. It cost $32 for each of them what was the total cost for all of them to get in
topjm [15]
A group is around 4-8 people so i would go with 4 at first. 4x32= $128 so that’s your answer, hopefully!
8 0
3 years ago
How much 20% solution needs to be added to a 60% solution to make 400 ml of a 40% solution
Scorpion4ik [409]

Let x be the volume of 20% solution, y the volume of the 60% solution. We want a total volume of 400 mL in the final mixture, so

x+y=400

Each mL of either solution will contribute a corresponding concentration, and in the final mixture we want the 400 mL to have a 40% concentration, which means we should also have

0.2x+0.6y=0.4\times400=160

Solve the system and we get x=y=200\,\rm{mL}.

4 0
3 years ago
(secx)dy/dx=e^(y+sinx), please help me solve the differential equation. Thanks :)
nalin [4]
First, you must know these formula  d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx

(secx)dy/dx=e^(y+sinx), implies  <span>dy/dx=cosx .e^(y+sinx), and then 
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of 
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that   d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
 finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is 
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx
7 0
3 years ago
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