Answer:
First question: LCL = 522, UCL = 1000.5
Second question: A sample size no smaller than 418 is needed.
Step-by-step explanation:
First question:
Lower bound:
0.36 of 1450. So
0.36*1450 = 522
Upper bound:
0.69 of 1450. So
0.69*1450 = 1000.5
LCL = 522, UCL = 1000.5
Second question:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

The project manager believes that p will turn out to be approximately 0.11.
This means that 
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The project manager wants to estimate the proportion to within 0.03
This means that the sample size needed is given by n, and n is found when M = 0.03. So






Rounding up
A sample size no smaller than 418 is needed.
Use the website desmos.com
Answer:
Need more information
Step-by-step explanation:
Answer:
£7899
Step-by-step explanation:
Since the original price of the car is £8999 and £1100 is being given off in form of discount
So to determine the amount the car is being sold it will be
Original price - discount
8999-1100
7899
So the car is sold at £7899
1) 18
2) 4
3) 27
4) 9
5) x=8
6) x=6