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spin [16.1K]
3 years ago
10

BD and AC are chords that intersect at point Y.

Mathematics
2 answers:
butalik [34]3 years ago
7 0

Answer:

c 4

Step-by-step explanation:

test on edg

Sindrei [870]3 years ago
6 0

Answer:

4 units

Step-by-step explanation:

<u><em>The complete question is</em></u>

BD and AC are chords that intersect at point Y. A circle is shown. Chords B D and A C intersect at point Y. The length of B Y is 3, the length of Y D is 8, the length of A Y is x, and the length of Y C is 6. What is the length of line segment AY?

<u><em>The picture of the question in the attached figure</em></u>

we know that

The <u><em>Intersecting Chord Theorem</em></u> states that:  When two chords intersect each other inside a circle,the products of their segments are equal.

do

In this problem

(BY)(YD)=(AY)(YC)

substitute the given values

(3)(8)=(x)(6)

solve for x

24=6x\\x=24/6\\x=4\ units

therefore

The length of segment AY is 4 units

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Answer: The answer to this question is x=-1/2

Step-by-step explanation: Multiply the left hand side by - and the right hand side by 4 in order to remove the brackets. After removing the brackets we get: 5+6x=20x+12.

Then we add the like terms.

5-12=20x-6×

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3 0
3 years ago
Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE
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Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to 20\ units

Part 3) The area is equal to 25\ units^{2}

Step-by-step explanation:

we have

A(5,0), B(2,4), C(-2,1),D(1,-3)

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

A(5,0),B(2,4)

substitute in the formula

d=\sqrt{(4-0)^{2}+(2-5)^{2}}

d=\sqrt{(4)^{2}+(-3)^{2}}

d=\sqrt{25}

AB=5\ units

Find the distance BC

B(2,4), C(-2,1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}

BC=5\ units

Find the distance CD

C(-2,1),D(1,-3)

substitute in the formula

d=\sqrt{(-3-1)^{2}+(1+2)^{2}}

d=\sqrt{(-4)^{2}+(3)^{2}}

d=\sqrt{25}

CD=5\ units

Find the distance AD

A(5,0),D(1,-3)

substitute in the formula

d=\sqrt{(-3-0)^{2}+(1-5)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}        

AD=5\ units

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

B(2,4),D(1,-3)

substitute in the formula

d=\sqrt{(-3-4)^{2}+(1-2)^{2}}

d=\sqrt{(-7)^{2}+(-1)^{2}}

BD=\sqrt{50}\ units        

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

BD^{2}=AD^{2}+AB^{2}

substitute

(\sqrt{50})^{2}=5^{2}+5^{2}

50=50 -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

A=b^{2}

we have

b=5\ units

A=5^{2}=25\ units^{2}

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

P=4b

we have

b=5\ units

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Which measurement is equal to 20 cups? 40 pints 320 fluid ounces 5quarts 1gallon?
Marina CMI [18]
<span>20 Cups = 160 Fluid Ounces
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Answer:

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A = 5.2 * 4.8

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