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AleksandrR [38]
3 years ago
11

If sinФ = 1/6 . what are the values of cosФ and tanФ? Show steps

Mathematics
2 answers:
Marianna [84]3 years ago
8 0

sinФ = 1/6

sinФ = opposite/hypotenuse

cosФ = adjacent/hypotenuse

tanФ = opposite/adjacent

SOHCAHTOA

1^(2)+b^(2)=6^(2)

1+b^(2)=36

b^(2)=35

\sqrt{35}

cosФ = \sqrt{35}/6

tanФ = 1/\sqrt{35} = \sqrt{35}/35

BartSMP [9]3 years ago
6 0

Answer:

Cos ø = √35/6

Tan ø = √35/35

Step-by-step explanation:

Sin ø = opposite/hypothenus

Sin ø = 1/6

Pythagoras theorem says

Hyp² = Opp² + Adj²

6² = 1² + A²

A² = 35

A = √35

Hence, cos ø = √35/6

tan ø = 1/√35 = √35/35

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