So long as the perimeters are the same, rectangles and squares share the same area. For example, a square that is 2m by 2m across is 4m squared. A rectangle of 4m by 1m across is still 4m squared.
Therefore all we want to do here is see how big we can make our “square” perimeter using the creek. We have three sides to spread 580ft across, therefore if we divide this by 3, we get 193.3ft of fencing per side. If we then square this figure, we will then get the maximum possible area, which comes to 37,377ft squared. (That’s a huge garden).
Think of it this way: Lets add numbers in pairs, starting at the very outer 2 numbers (19 and 77) then go in by one and add the second number and the second to last (20 and 76), then (21 and 75) and so on. The sum of all of these pairs are all the same: 96. How many 96s will we have? Well since we're coming from each end toward the middle adding pairs we will have half the distance between 19 and 77, that is (77-19)/2 = 29. So we can actually just take 96*29 = 2784. This is the sum of all numbers between 19 and 77
Answer:
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Answer:
Step-by-step explanation:
The two dump intervals have a greatest common factor (GCF) of 3, so their least common multiple (LCM) is ...
(18)(21)/3 = 126 . . . . minutes
This period is 2 hours 6 minutes. The last time both dumped was 1:10, so the next time both will dump is ...
1:10 +2:06 = 3:16 . . . P.M.
and the next time after that is ...
3:16 +2:06 = 5:22 . . . P.M.
