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3 years ago

Which term best describes the geometric figure?

Mathematics

2 answers:

77julia77 [94]3 years ago

8 0

Answer:

D. Segment.

Step-by-step explanation:

We have been given a geometric figure. We are asked to determine the name of the figure.

We can see that our given has two points that are defined by points A and B.

Let us check our given choices one by one.

A. Line

A line has no endpoints, it goes in both directions forever. Therefore, option A is not a correct choice.

B. Point

A point is defined by a location on coordinate plane. It has no size, therefore, option B is not correct as well.

C. Ray

A ray goes into one direction forever, therefore, option C is not correct.

D. Segment.

We know that a line segment is a part of a line that is bounded by two distinct end points. A segment contains every point on the line between its endpoints.

Therefore, option D is the correct choice.

nordsb [41]3 years ago

5 0

Answer:

The geometric figure is a Segment

Step-by-step explanation:

A and B are points since they are shown by dots and a point usually marks a location.

In Geometry a line is straight and extends in both directions infinitely.

A line segment or simply segment is the part of a line that connects two points. A segment is the shortest distance between the two points and has a length.

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Answer:

The volume of pyramid B is 64 times the volume of pyramid A.

Step-by-step explanation:

Given:

Two square pyramids A and B.

Side Length of A, $s_A =$ 12 inches

Height of A, $h_A =$ 8 inches

Side Length of B, $s_B =$ 48 inches

Height of B, $h_B =$ 32 inches

To find:

How many times bigger is the volume of pyramid B than pyramid A?

$V_B$ is how many times bigger than $V_A$ ?

Solution:

First of all, let us have a look at the formula for volume of a pyramid:

$V=\dfrac{1}{3} \times \text{Area of Base} \times \text{Height}$

Here, base is square, so:

$V=\dfrac{1}{3} \times s^2 \times h$

Volume of pyramid A:

$V_A=\dfrac{1}{3} \times s_A^2 \times h_A$

$\Rightarrow V_A=\dfrac{1}{3} \times 12^2 \times 8 = 384\ inch^3$

Volume of pyramid B:

$V_B=\dfrac{1}{3} \times s_B^2 \times h_B$

$\Rightarrow V_B=\dfrac{1}{3} \times 48^2 \times 32 \\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 4^2 \times 4\\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 64\\\Rightarrow V_B= 24576\ inch^3 = 384\times 64\ inch^3\\\Rightarrow V_B = V_A\times 64\ inch^3$

The volume of pyramid B is 64 times the volume of pyramid A.

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