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Trava [24]
3 years ago
6

3p + 7 = -4(4 - 6p) + 2

Mathematics
2 answers:
rewona [7]3 years ago
7 0

Answer:

p = 1

Step-by-step explanation:

Given

3p + 7 = - 4(4 - 6p) + 2 ← distribute and simplify right side

3p + 7 = - 16 + 24p + 2

3p + 7 = 24p - 14 ( subtract 3p from both sides )

7 = 21p - 14 ( add 14 to both sides )

21 = 21p ( divide both sides by 21 )

1 = p , that is p = 1

zvonat [6]3 years ago
3 0

p=1

Step-by-step explanation:

3p + 7 =  - 4(4 - 6p) + 2 \\ 3p + 7 =  - 16 + 24p + 2 \\ 3p - 24p =  - 16 + 2 - 7 \\  - 21p =  - 21

\frac{ - 21p}{ - 21}  =  \frac{ - 21}{ - 21}  \\ p = 1

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−15x+4≤109 OR −6x+70>−2
Xelga [282]

-15x+4\leq109\qquad\text{subtract 4 from both sides}\\\\-15x\leq105\qquad\text{change the signs}\\\\15x\geq-105\qquad\text{divide both sides by 15}\\\\\boxed{x\geq-7}\\or\\-6x+70>-2\qquad\text{subtract 70 from both sides}\\\\-6x>-72\qquad\text{change the signs}\\\\6x

3 0
3 years ago
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I need help right now with homework plz.<br><br>both of them are on the same homework page.
katovenus [111]

Answer:

For the first one I believe it is 90

Step-by-step explanation:

All I did to solve this was do 180 which is the diameter and divide by 2

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3 years ago
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Not sure need help ​
kvasek [131]

Answer:

X = 3

Step-by-step explanation:

So do 7-2 which equals 5. 5 times 6 because 6 is outside of the parentheses with no symbol, so that means to multiply. That would equal 30. You want your answer to equal 6, so you would want the number inside of the parentheses to be 1, so that 1 times 6 would be 6. 2 x 3 would be sixe, and then 7-6 would equal one. 1 times 6 would be 6. So there is your answer.

4 0
3 years ago
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The recursive function LaTeX: f\left(0\right)=1,\:f\left(n\right)=f\left(n-1\right)+2nf ( 0 ) = 1 , f ( n ) = f ( n − 1 ) + 2 n
m_a_m_a [10]

Question:

The recursive function f(0) = 1, f(n) = f(n-1) + 2n represents the nth term of a sequence. Determine the explicit function

Answer:

f(n) = n^2 + n+1

Step-by-step explanation:

Given

f(0) = 1

f(n) = f(n-1) + 2n

Required

Write an explicit formula

Let n = 1

f(1) = f(1-1) + 2*1

f(1) = f(0) + 2

f(1) = 1 + 2 = 3

Let n = 2

f(2) = f(2-1) + 2*2

f(2) = f(1) + 4

f(2) = 3 + 4 = 7

Let n =3

f(3)=f(3-1) + 2 * 3

f(3)=f(2) + 6

f(3)=7+ 6 = 13

Let n = 4

f(4) = f(4 - 1) + 2 * 4

f(4) = f(3) + 8

f(4) = 13+ 8 = 21

So, we have:

f(1) = 3= 1 + 2 * 1=1+0*1*2*1

f(2) = 7= 3 + 2 * 2=1+1*2+2*2  

f(3) = 13= 7 + 2 * 3= 1+2*3+2*3

f(4) = 21 = 13 + 2 * 4= 1+3*4 +2 *4

Following the above pattern:

f(n) = 1 + (n - 1) * n + 2 * n

f(n) = 1 + n(n - 1) + 2n

Open bracket

f(n) = 1 + n^2 - n + 2n

f(n) = 1 + n^2 + n

f(n) = n^2 + n+1

3 0
2 years ago
What is an expression that has a value of 35 when p=7
andre [41]
5p = 35
Hope this helps!
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3 years ago
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