Question

Jenna drives on average 46 miles per day with a standard deviation of 5.3 miles per day. Suppose Jenna's miles driven per day are normally distributed. Let X = the number of miles driven in a given day. Then X - N(46, 5.3). If necessary, round to three decimal places.
Provide your answer below:
Suppose Jenna drives 41 miles on Monday. The Z-score when x - 41 is______ . The mean is________ This z-score tells you that x = 41 is________ standard deviations to the left of the mean.

Answer 1

Answer:

Suppose Jenna drives 41 miles on Monday. The Z-score when x - 41 is    $-0.943$.   The mean is  $46$  This z-score tells you that x = 41 is  $0.94$  standard deviations to the left of the mean.

Step-by-step explanation:

From the question we are told that

  The  mean is  $\= x = 46\ miles / day$

  The standard deviation is  $\sigma = 5.3 \ miles \ per \ day$

   The  value of =  41

Generally the z-score is mathematically represented as

        $z = \frac{x-\= x}{\sigma }$

substituting values  

         $z = \frac{41-46}{5.3}$

          $z = - 0.943$