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ANTONII [103]
3 years ago
12

Form a polynomial whose real zeros and degree are given. ​zeros: negative 2−2​,negative 1−1​,44​, 55​; ​ degree: 4 type a polyno

mial with integer coefficients and a leading coefficient of 1.
Mathematics
1 answer:
prisoha [69]3 years ago
6 0
We write the polynomial in its factored form first.
 We have then:
 (x + 2) * (x + 1) * (x-4) * (x-5)
 We now rewrite the polynomial:
 (x ^ 2 + x + 2x + 1) * (x ^ 2-5x-4x + 20)
 (x ^ 2 + 3x + 1) * (x ^ 2-9x + 20)
 x ^ 4 - 9x ^ 3 + 20x ^ 2 + 3x ^ 3 - 27x ^ 2 + 60x + x ^ 2 - 9x + 20
 We now add terms of the same degree:
 x ^ 4 + (-9 + 3) x ^ 3 + (20-27 + 1) x ^ 2 + (60-9) x + (20)
 x ^ 4 + (-6) x ^ 3 + (-6) x ^ 2 + (21) x + (20)
 x ^ 4 - 6x ^ 3 - 6x ^ 2 + 21x + 20
 Answer:
 
The polynomial sought is:
 
x ^ 4 - 6x ^ 3 - 6x ^ 2 + 21x + 20
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HACTEHA [7]

Answer:

x=70

Step-by-step explanation:

Angle 1 will be 90° when it subtends a 180° arc. That means the sum of 100° and (x+10) must be 180°, so (x+10) = 80°.

We assume this is intended to mean ...

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_____

If the intent is (x+10°) = 80°, then x=70°.

_____

<em>Comment on the numbers here</em>

Units need to be properly specified in problems of this nature. <em>As written</em>, we probably should assume that 10 is <em>radians</em>, and x is a large negative number, about -8.60374 (radians), or -492.958°.

A number of radians is a "pure number." It has <em>no units</em>. The term "radians" is used to signify that the number is considered to be an angle measure.

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