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3 years ago

Which proportion could be used to determine if the figures represent a dilation? 2/3=5/8, 2/3=8/5, 2/8=5/3, or 2/8=3/5?

Mathematics

1 answer:

Maurinko [17]3 years ago

5 0

Answer:

The answer is A. 2/3 =5/8

Step-by-step explanation:

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In a company, 80% of the workers are women. If 480 men work for the company, how many workers are there in all? Use pencil

nekit [7.7K]

Answer:

The total workers are 2400.

Step-by-step explanation:

Given:

In company 80% of the workers are women.

480 workers are men.

Now, to find the total workers in all.

In first way:

If women are 80%, then men would be 100-80 = 20%.

Let the total workers be $x$ .

According to question:

$20\%\ of \ x=480$

⇒ $\frac{20}{100} \times x=480$

⇒ $0.20\times x=480$

⇒ $0.20x=480$

Dividing both sides by 0.20 we get:

⇒ $x=2400$ .

Total workers = 2400.

Now, in second way.

Again, let the total workers be $x$ .

According to question:

$x-80\%\ of\ x=480$

⇒ $x-\frac{80}{100}\times x=480$

On solving:

⇒ $x-0.80x=480$

⇒ $0.20x=480$

Dividing both sides by 0.20 we get:

⇒ $x=2400$ .

Total workers = 2400.

Therefore, the total workers are 2400.

7 0

3 years ago

Factor x^4 + x y^3 + x^3 + y^3 completely. Show your work.

andrey2020 [161]

$\bf x^4+xy^3+x^3+y^3\impliedby \textit{now let's do some grouping}
\\\\\\
(x^4+xy^3)~~+~~(x^3+y^3)\implies x(x^3+y^3)~~+~~(x^3+y^3)
\\\\\\
\stackrel{\stackrel{common}{factor}}{(x^3+y^3)}(x+1)\\\\
-------------------------------\\\\
\textit{now recall that }\qquad \qquad \textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
a^3-b^3 = (a-b)(a^2+ab+b^2)\\\\
-------------------------------\\\\
(x+y)(x^2-xy+y^2)(x+1)$