2+2=4 so now its 4/4*10. 4*10 is 40 so now its 4/40. Dividing both sides by 4 will get you the simplest form 1/10
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
Answer:
D
Step-by-step explanation:
EXPLORE test is the college test ACT's "prep" version mostly for 8th and 9th graders.
ASVAB (Armed Services Vocational Aptitude Battery) test is used for military entrance exam.
PLAN is also like EXPLORE that it is a "prep" test for ACT but usually given to sophomore (10th grade) students. This has been discontinued from 2014, though.
SAT is a standardized test administered by College Board and is a widely used common Undergraduate University admissions exam. Colleges use this to make admissions decisions.
Thus, D is the correct choice.
