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blondinia [14]
3 years ago
13

True or false need help

Mathematics
2 answers:
m_a_m_a [10]3 years ago
6 0

I would think the answer would be true


Sedbober [7]3 years ago
4 0
If they both have the same angles then it’s true
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Carter has one 20$ bill, one 10$bill, four 5$ bills and two 1$ bill,Aubrey has two 10$bills ,five 5$ bills and seven 1$ bills .w
Luba_88 [7]
Carter- 20+10=30+(5x4)=50+2=$52
Aubrey- 10x2=20+(5x5)=45+7=$52
They both have the same amount of money
8 0
2 years ago
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A rectangle has a height of 5m^4 and a width of m^2-2m-1.
In-s [12.5K]

Answer:

area of the rectangle = 5(m⁶ - 2m⁵ - m⁴) or 5m⁴(m² - 2m - 1)

Step-by-step explanation:

The rectangle has a height of 5m⁴ and the width is m² - 2m - 1.The area of the rectangle is the product of the width and the height.

width =  m² - 2m - 1

height = 5m⁴

area of rectangle = 5m⁴ × (m² - 2m - 1)

area of rectangle = 5m⁴(m² - 2m - 1)

area of the rectangle = 5m⁶ - 10m⁵ -  5m⁴

area of the rectangle = 5(m⁶ - 2m⁵ - m⁴)

The area of the entire rectangle can be expressed as 5(m⁶ - 2m⁵ - m⁴) or 5m⁴(m² - 2m - 1)

8 0
2 years ago
Read 2 more answers
Find the sine ratio of angle X. Hint: Use the slash symbol ( / ) to represent the fraction bar, and enter the fraction with no s
dybincka [34]
Sin A = 28/35 = 4/5 =0.8
6 0
2 years ago
What is the solution to the following system of equations?
Alchen [17]

Answer:

it has infinitely many solutions

3 0
3 years ago
HELP Use either law of sines or law of cosine. Need help on this problem! show work please!​
Marina86 [1]

Answer: x = 15.035677095729 approximately

Round this however you need to.

=================================================

Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

sin(Q)/q = sin(R)/r

sin(Q)/PR = sin(R)/PQ

sin(Q)/13 = sin(85)/19

sin(Q) = 13*sin(85)/19

sin(Q) = 0.6816068987

Q = arcsin(0.6816068987) ... or ... Q = 180-arcsin(0.6816068987)

Q = 42.9693397461 ... or ... Q = 137.0306602539

These values are approximate.

----------------

Now if Q = 42.9693397461 approximately, then angle P is

P = 180-Q-R

P = 180-42.9693397461-85

P = 52.0306602539

Similarly, if Q = 137.0306602539 approximately, then,

P = 180-Q-R

P = 180-137.0306602539-85

P = -42.0306602539

A negative angle is not possible, so we'll ignore Q = 137.0306602539

----------------

The only possible value of angle P is approximately P = 52.0306602539

Let's apply the law of sines again to find side p, aka segment QR

sin(P)/p = sin(R)/r

sin(P)/QR = sin(R)/PQ

sin(52.0306602539)/x = sin(85)/19

19*sin(52.0306602539) = x*sin(85)

19*sin(52.0306602539)/sin(85) = x

x = 15.035677095729

This value is approximate.

Round this value however you need to.

4 0
2 years ago
Read 2 more answers
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