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snow_tiger [21]
3 years ago
10

A bag of M&M's has 2 red, 7 green, 3 blue, and 6 yellow M&M's. What is the probability of randomly picking each of the f

ollowing? (Round to 4 decimal places)
Mathematics
1 answer:
Sauron [17]3 years ago
8 0

Answer:

do you still need help with this?

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Drag each expression to the correct location on the model. Not all will be used
grandymaker [24]

Answer:     \dfrac{x^{2}+2x+1 }{\mathbf {x-1}} \cdot \dfrac{\mathbf {5x^{2} +15x-20} }{7x^{2} +7x}

Step-by-step explanation:

\dfrac{\dfrac{5x^{2} +25x+20}{7x} }{\dfrac{x^{2} +2x+1}{7x^{2} +7x} } =\dfrac{5x^{2} +25x+20}{7x} \times \dfrac{7x^{2} +7x}{x^{2} +2x+1}=\dfrac{5x^{2} +25x+20}{7x} \times \dfrac{7x(x +1)}{(x+1)^{2} }=\\\\=\dfrac{5x^{2} +25x+20}{x+1} =\dfrac{{5(x+1)(x+4)}}{x+1}=5(x+4)

5(x+4)=\dfrac{5(x-1) \cdot (x+4)}{x-1}=\dfrac{5x^{2} +15x-20}{x-1}

<em>Thus, the expressions will be used: (5x² + 15x - 20) and (x + 4).</em>

<em>Let's check:</em>

\dfrac{x^{2}+2x+1 }{\mathbf {x-1}} \cdot \dfrac{\mathbf {5x^{2} +15x-20} }{7x^{2} +7x} =\dfrac{(x+1)^{2} }{x-1}  \cdot \dfrac{5(x-1) \cdot (x+4)}{7x(x+1)} =\\\\=\dfrac{(x+1) \cdot 5 \cdot (x+4)}{7x} =\dfrac{5x^{2} +25x+20}{7x}

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Step-by-step explanation:

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Step-by-step explanation:

big brain time

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answer si 24
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