Answer:
No, 
Step-by-step explanation:
each row can not have the same number of trees as the number 987 can not be evenly divided into 9 rows. 
 
        
                    
             
        
        
        
Answer:
40
Step-by-step explanation:
This is asking you to plug in the value of h(5) into g(x). First solve for h(5)
x^2-3 = h(x)
5^2-3= 22
h(5) = 22 
h(5) is 22. So now, plug that into g(x).
g(h(5)) = 2(22)-4
44-4=40
(g.h)(5) is 40.
 
        
             
        
        
        
Yellow:blue is a ratio of 2:3, meaning that 2/5 of the desired mixture is yellow. From this, you need to find how much yellow is necessary for 20 ounces. Well, 2/5 of the 20 ounces will be yellow paint, while the other 3/5 will be blue. So she will need 8 ounces of yellow paint to get 20 ounces of the desired mixture. Hope this helps! :)
        
                    
             
        
        
        
Using the normal distribution, it is found that there is a 0.0005 = 0.05% probability of getting more than 66 heads.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean  and standard deviation
 and standard deviation  is given by:
 is given by:

- The z-score measures how many standard deviations the measure is above or below the mean. 
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with  . .
For the binomial distribution, the parameters are given as follows:
n = 100, p = 0.5.
Hence the mean and the standard deviation of the approximation are given as follows:
 . .
Using continuity correction, the probability of getting more than 66 heads is P(X > 66 + 0.5) = P(X > 66.5), which is <u>one subtracted by the p-value of Z when X = 66.5</u>.


Z = 3.3
Z = 3.3 has a p-value of 0.9995.
1 - 0.9995 = 0.0005.
0.0005 = 0.05%
More can be learned about the normal distribution at brainly.com/question/4079902
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