Answer:
y = 18
x = 7
Step-by-step explanation:
Because the angle with the size of 11x - 9 is along a straight line, the opposite angle is also the same. This means that we have a complete equation for the second triangle:
6x - 2 + 72 + 11x - 9 = 180
72 - 2 - 9 + 6x + 11x = 180
61 + 17x = 180
Now, to solve x we need to subtract 61 from both sides to isolate the 17x:
61 + 17x - 61 = 180 - 61
17x = 119
Divide both sides by 17:
x = 7
Now we have the x variable to put into the second triangle equation.
We also have the total angles for the other triangle:
30 + 11x - 9 + 5y - 8
30 - 9 - 8 + 11x + 5y
13 + 11x + 5y = 180
Substitute in the x variable:
13 + 11(7) + 5y = 180
13 + 77 + 5y = 180
90 + 5y = 180
Subtract 90 from both sides of the equation:
90 + 5y - 90= 180 - 90
5y = 90
Divide both sides by 5:
y = 18
Hope this helps!
Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is
<u>Solution:</u>
Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).
Generic slope intercept form of a line is given by y = mx + c
where m = slope of the line.
Let's first find slope intercept form of 3x + y = -8
3x + y = -8
=> y = -3x - 8
On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3
And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.
Let required slope = x
So we need to find the equation of a line whose slope is and passing through (-3,1)
Equation of line passing through and having lope of m is given by
Substituting the values we get,
Hence the required equation of line is found using slope intercept form