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3 years ago

R+2r=105 what is answer

Mathematics

1 answer:

Alik [6]3 years ago

8 0

Answer:

If you're trying to solve for r. r=35

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

r+2r=105

(r+2r)=105(Combine Like Terms)

3r=105

Step 2: Divide both sides by 3.

3r/3 = 105/3

r=35

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Lynn has a box of crayons.

Scrat [10]

Answer:

<em>There are 72 crayons in the box</em>

Step-by-step explanation:

<u>Fractions</u>

To solve this problem we'll manage numbers as fractions to keep the precision up to the end of it.

Lynn has a box of crayons. It's given 4/9 of the crayons are blue. The remaining crayons are:

$1-\frac{4}{9}=\frac{5}{9}$

From that portion, 65% are red, or equivalently, 35% are yellow.

We write 35% as a fraction:

$\displaystyle 35\%=\frac{35}{100}=\frac{7}{20}$

Thus, the portion of yellow crayons is:

$\displaystyle \frac{7}{20}\cdot \frac{5}{9}=\frac{7}{36}$

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3 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form

Over [174]

Answer:

$\vec{v}= \text{ or } \approx$

Step-by-step explanation:

Component form of a vector is given by $\vec{v}=$ , where $i$ represents change in x-value and $j$ represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector $\vec{v}=$ , the magnitude is $||v||=\sqrt{i^2+j^2$ .

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being $i$ , one leg being $j$ , and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

$\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}$

To find the other leg, $i$ , we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

$\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}$