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umka2103 [35]
3 years ago
13

You deposit $10,000 into a bank account at 2% annual interest. How long will it take for the $10,000 to compound to $30,000?

Mathematics
1 answer:
Rama09 [41]3 years ago
8 0

Answer: <em>time = 55.48 years</em>

Explanation:

Given:

Principal amount = $10000

Interest rate = 2% p.a

Amount = $30000

We can evaluate the time taken using the following formula:

Amount=Principal(1+\frac{r}{100})^{t}

30000 = 10000\times(1+\frac{2}{100})^{t}

Solving the above equation, we get

1.02^{t} = 3

Now taking log on both sides, we get;

t\ log(1.02) = log(3)

<em>time = 55.48 years</em>

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fgiga [73]

Answer:

well for me

Step-by-step explanation:

7 mins

7×60

=420

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450 sec

450/3600×100

45000/3600

450/36

12.5

that's how I can help

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64 = (3x+1) Find the value of x. A) 21 B) 27 C) 31 D) 34
krek1111 [17]

Take away 1 from either side so the equation becomes 63=3x then divide both sides by 3 so it becomes 21=x which is your answer (option A)

7 0
4 years ago
What is 5 2/5 multiplied by 2 as a mixed number or fraction
erica [24]

Answer:

54/5

Step-by-step explanation:

So 5 2/5 is 27/5 . So 54/5

5 0
3 years ago
The graph of f(x) = x2 is shifted 3 units to the left to obtain the graph of g(x). Which of the following equations best describ
ANTONII [103]

Answer:

g(x) = (x + 3)^2

Step-by-step explanation:

When a function is shifted to the left or right we can think of a change of units, like a new independent variable is used.

If we have a quadratic function

f(x)=x^2

and the graph is shifted 3 units to the left, then we can think of a new unit u that is:

g(x)=u^2

The vertix of this parabola, that happens for u=0, happens for x=-3, as the graph is shifted 3 units to the left.

Then, the relation between u and x is:

u-x=0-(-3)=3\\\\u=x+3

We can use this relation in the new graph and replace u as:

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6 0
3 years ago
The Friendly Sausage Factory (FSF) can produce hot dogs at a rate of 5,750 per day. FSF supplies hot dogs to local restaurants a
NARA [144]

Answer:

A) 22812 hotdogs per run

B) 75 runs/yr

C) 4 days in a run

Step-by-step explanation:

We are given;

Production rate;p = 5750 per day

Steady Usage rate;u = 270 per day

Setup cost of hotdog;S = $67

Annual carrying cost (H) = 47 cents = $0.47 per hot dog

No. of Production days; d = 297 days

A) Let's first find the annual demand given by the formula;

Annual demand;D = pd

D = 5750 × 297

D = 1707750 hot dogs/yr

Now, formula for optimal run size is given by;

Q_o = √[(2DS/H) × (p/(p - u))]

Plugging in the relevant values gives;

Q_o = √[(2 × 1707750 × 67/0.47) × (5750/(5650 - 270))]

Q_o =√520375454.7971209

Q_o = 22812 hotdogs per run

B) formula for Number of runs per year is given as;

No. of Runs = D/Q₀

Thus;

no. of runs = 1707750/22812

no. of runs ≈ 75 runs/yr

C) Length of a run is given by the formula;

Length = Q₀/p

Length = 22812/5750

Length ≈ 4 days in a run

6 0
3 years ago
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