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Ket [755]
3 years ago
12

I would really appreciate some help.

Mathematics
1 answer:
VLD [36.1K]3 years ago
7 0
2 to the power of 61 is = 2305843009213694000

then just minus that by 1 and divide it by 3. if it’s divisible then it’s a multiple of 3.
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2,000 pencils are being divided into packages of 15. How many pencils will be left over?
Mashcka [7]
You have 133 pencils left.

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3 years ago
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If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No
Effectus [21]

If A and B are independent, then P(A\cap B)=P(A)P(B).

a.

P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)

P(A\cup B)=0.5+0.2-0.5\cdot0.2

\boxed{P(A\cup B)=0.6}

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)

P(A^c\cap B^c)=1-0.6

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c. DeMorgan's law can be used here too:

P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)

P(A^c\cup B^c)=1-0.5\cdot0.2

\boxed{P(A^c\cup B^c)=0.9}

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3 years ago
A solid oblique pyramid has a square base with edges measuring x cm. The height of the pyramid is (x + 2) cm. Which expression r
zavuch27 [327]

we know that

the volume of a solid oblique pyramid is equal to

V=\frac{1}{3}*B*h

where

B is the area of the base

h is the height of the pyramid

in this problem we have that

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B=b^{2}

where

<u>b=x\ cm</u>

so

B=x^{2}\ cm^{2}

h=(x+2)\ cm

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V=\frac{1}{3}*x^{2}*(x+2)\\ \\V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}

therefore

<u>the answer is</u>

V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}

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kirill [66]
3x - 5 = 2x is the equation
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Answer:

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Step-by-step explanation:

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