2 more than the sum of a number and 5

Fatoumata just accepted a job at a new company where she will make an annual salary of $64000. Fatoumata was told that for each

Nadya [2.5K]

Answer:

After 7 years: $81,500

If x=salary and t=years with company, then x=6400+2500t

Step-by-step explanation:

6 0

3 years ago

What is the base plan for the set of stacked cubes?

mash [69]

Answer:

i think it is the 3 one from the left side

Step-by-step explanation:

7 0

3 years ago

In the first four months of the year, Noralie's jewelry sales were declining. After April, her sales began to improve. The funct

Aleksandr-060686 [28]

Is your function y= { -x+8, if x<4 x, if x is greater than or=4? Cause if so then yes, your answer would be true then

4 0

4 years ago

I need help. Please solve this using GEMS. Take a photo of your work and attach it to your answer. Please help.

crimeas [40]

Answer:

120

Step-by-step explanation:

45 ÷ 3 x 2³

2³ = 8

45 ÷ 3 x 8

45 ÷ 3 = 15

15 x 8 = 120.

Hope this helped.

P.S. do I have to put in a photo?

8 0

3 years ago

A study is conducted to determine if a newly designed text book is more helpful to learning the material than the old edition. T

CaHeK987 [17]

Answer:

We need to conduct a hypothesis in order to check if the mean is higher than 75, the system of hypothesis are :

Null hypothesis: $\mu \leq 75$

Alternative hypothesis: $\mu > 75$

A. One-Tailed

$z=\frac{82.2-75}{\frac{10.4}{\sqrt{10}}}=2.189$

$p_v =P(z>2.189)=0.0143$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Data given and notation

We have the following data: 84 94 80 88 77 68 90 74 96 71

We can calculate the sample mean with the following formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X=82.2$ represent the sample mean

$\sigma=10.4$ represent the population standard deviation

$n=10$ sample size

$\mu_o =75$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 75, the system of hypothesis are :

Null hypothesis: $\mu \leq 75$

Alternative hypothesis: $\mu > 75$

A. One-Tailed

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{82.2-75}{\frac{10.4}{\sqrt{10}}}=2.189$

P-value

Since is a ONE-TAILED test the p value would given by:

$p_v =P(z>2.189)=0.0143$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

5 0

3 years ago