Class A 41, 42, 45, 46, 47, 48, 52, 53, 54, 59, 61, 61, 64, 68, 71, 82, 85, 90
Class B 41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95 ------------------------------------------------------------------------------------------------------ First we are going to find the mode and mean of class A
The mode is the number that appears the most
The number that appears the most is 61
The mode is 61
To find the mean you add all the numbers together and divide the sum by the amount of numbers added
The mode is 61 and the mean is 59.39 for class A ------------------------------------------------------------------------------------------------------ We are going to find the range and median for class B
To find the range you subtract the smallest number from the largest on
The smallest number is 41 The largest number is 95
Subtract these
95 - 41 = 54
The range is 54
To find the median you list the numbers from least to greatest and look for the number in the middle
The range is 54 and the median is 78 ------------------------------------------------------------------------------------------------------ Hope this helps!
The total number of members should be the sum of the number of men, x, and women, y, and that should be equal to 150. In mathematical equation that should be,
<em>x + y = 150</em>
If we are to note that there are 34 more men than women in the team, we can say that, y = x - 34
The equation then would become, x + (x - 34) = 150
The value of x from the equation is equal to 92. With this, the number of the women is equal to 58.