All categories

3 years ago

What is the mode and mean for class A and the range and medium for class B????

Mathematics

1 answer:

melamori03 [73]3 years ago

6 0

Hello!

First you have to list the data in both classes

Class A
41, 42, 45, 46, 47, 48, 52, 53, 54, 59, 61, 61, 64, 68, 71, 82, 85, 90

Class B
41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95
------------------------------------------------------------------------------------------------------
First we are going to find the mode and mean of class A

The mode is the number that appears the most

The number that appears the most is 61

The mode is 61

To find the mean you add all the numbers together and divide the sum by the amount of numbers added

41 + 42 + 45 + 46 + 47 + 48 + 52 + 53 + 54 + 59 + 61 + 61 + 64 + 68 + 71 + 82 + 85 + 90 = 1069

Divide this by the amount of numbers added

1069 / 18 = 59.3888...

The mean is 59.3888

The mode is 61 and the mean is 59.39 for class A
------------------------------------------------------------------------------------------------------
We are going to find the range and median for class B

To find the range you subtract the smallest number from the largest on

The smallest number is 41
The largest number is 95

Subtract these

95 - 41 = 54

The range is 54

To find the median you list the numbers from least to greatest and look for the number in the middle

41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95

The number in the middle is 78

The range is 54 and the median is 78
------------------------------------------------------------------------------------------------------
Hope this helps!

You might be interested in

A. vertical angles<br> b. complementary angle<br> c. supplementary angle<br> d. none of the above

Elis [28]

Answer:

C) supplementary angles

Step-by-step explanation:

C) supplementary angles

They add up to 180.

8 0

2 years ago

What is the length of side BD?

VashaNatasha [74]

Answer: 26.1

<u>Step-by-step explanation:</u>

$cos\theta=\dfrac{adjacent}{hypotenuse}\\\\\\cos(40^o)=\dfrac{20}{BD}\\\\\\BD=\dfrac{20}{cos(40^o)}\\\\\\BD=26.1$

4 0

3 years ago

Read 2 more answers

Jessica's Furniture Store manager is trying to figure out how much to charge for an armchair that just arrived. The chair was pu

VARVARA [1.3K]

Answer: The manager should sell the chair for $1740.

Step-by-step explanation:

45% of 1200 Solve this to find the amount increase

0.45 * 1200 = 540 Now add this amount to find the price.

$1200 + $540 = $1740

or you could do it this way

100% + 45% = 145%

145% of 1200 =?

1.45 * 1200 = 1740

3 0

2 years ago

Please answer this correctly without making mistakes

Pavlova-9 [17]

Answer:

This is what internet says. Maybe this helps.

4 0

2 years ago

PLEASE HELP ME!!! I WILL GIVE ALL THESE POINTS

WINSTONCH [101]

<h2>Answer and Explanation to questions 13,14,15</h2>

13) $\mathbf{\overline{XY}\cong\overline{CD}}$ as given in the question.

14) $\mathbf{\overline{XY}\cong\overline{YZ}}$ Since Y is the midpoint of XZ. So, Y will divide XZ in equal halves into XY and YZ.

15) $\mathbf{\overline{CD}\cong\overline{YZ}}$

$\because\overline{\textrm{XY}}\cong\overline{\textrm{CD}}$ and $\overline{\textrm{XY}}\cong\overline{\textrm{YZ}}$ . So, $\overline{\textrm{CD}}\cong\overline{\textrm{YZ}}$

<h2>Answer and Explanation to questions 16,17,18</h2>

∠3 is supplementary to ∠1 means: ∠3 + ∠1 = 180°

And, according to figure ∠1 + ∠2 = 180° as ∠1 and ∠2 form a straight line.

∠3 + ∠1 = 180° .............(i)

∠1 + ∠2 = 180° .............(ii)

subtracting equation (i) and (ii) will give ∠3 = ∠2 ..........(iii)

15) ∠3 is supplementary to ∠1 as given in the question

16) ∠2 is supplementary to ∠1 as shown be equation (ii)

18) ∠3 ≅ ∠2 as shown by equation (iii)

<h2>Answer and Explanation to questions 19</h2>

∠3 and ∠4 form a straight line. Therefore, ∠3 + ∠4 = 180° .......(i)

∠4 and ∠5 form a straight line. Therefore, ∠4 + ∠5 = 180° .......(ii)

subtracting equation (i) and (ii)

∠3 + ∠4 - (∠4 + ∠5) = 180°-(180°)

∠3 + ∠4 - ∠4 - ∠5 = 180°-180°

∠3 - ∠5 = 0

∴ ∠3 = ∠5 (Hence Proved)

4 0

2 years ago