Send a better picture so I can help.
What is the question exactly? What is it you are trying to find?
7 and 10 is half
so we expect the people come to wedding half of 120÷2=60 people
i just try
<u>Answer:</u>
2(-5 - 7j) = -10 - 14j
<u>Step-by-step explanation:</u>
Using the distributive property means that we have to multiply both -5 and -7j by 2:
2(-5 - 7j)
⇒ 2 × -5 + 2 × -7j
⇒ -10 - 14j
Hello, please consider the following.
We will multiply the numerator and denominator by

to get rid of the root in the denominator.
First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

We need to take any x real number different from 8/3 then and simplify the expression.
Let's do it!

Thank you