)
<span>tanx = 3/10 </span>
<span>x=16.7 B </span>
<span>2) </span>
<span>tan 64 = 173/x </span>
<span>x = 84.38 D </span>
<span>3) </span>
<span>tan21 = x/442 </span>
<span>x= 169.67 B </span>
<span>4) </span>
<span>tanx = 16.2/48.3 </span>
<span>x = 18.54 A </span>
<span>5) </span>
<span>tanx = 8/6.5 </span>
<span>x = 50.91 C </span>
<span>6) </span>
<span>tan89 = 1149/x </span>
<span>x=20.06 A </span>
<span>7) </span>
<span>tanx = 21/12 </span>
<span>x= 60.26 B </span>
<span>8) B </span>
<span>9) </span>
<span>tanx = 25/63 </span>
<span>x = 21.64 C </span>
<span>10) </span>
<span>tanx = 60/15 </span>
<span>x= 75.96 D</span>
Answer:
The relationship shows a direct linear variation with a constant of variation of 1.
Step-by-step explanation:
This is true because the slope of the equation is 1
Answer:
in short, Yes they are always rational.
here's why...
E.g. suppose 
and 
are fractions, that means that a,b,c,d are all integers, and b and d are not zero. finding the sum the numerator, and denominator would also have to be integers. the denominator of the sum can't be zero since the denominators of the fractions were not zero, and would give 
and since they are bound by addition (sum means addition) they must also be rational since eit would equal a bigger integer than initially had
Step-by-step explanation:
Answer:
A) 5/6
B) -67/30 (or) -2 7/30
A) -9/2 (or) -4 1/2
Step-by-step explanation:
A) 2/3(5)-5/2=3 1/3-5/2 = 10/3-5/2 = 20/6-15/6= 5/6
B) 2/3(2/5)-5/2= 4/15-5/2 = 8/30-75/30 = -67/30
A) 2/3(-3)-5/2=-2-5/2= -4 1/2
