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3 years ago

7

When calculating the slope of a line, the horizontal distance between two points on the line is called the "rise" and the vertic

al distance between the points is called the "run"
Is this statement True or False?

1 answer:

s2008m [1.1K]3 years ago

7 0

Answer: FALSE

The vertical line is Y (rise) and the horizontal line is X (run)

You might be interested in

Please help on this one plzzzz

deff fn [24]

We know that Angle Bisector Divides an Angle into Two Equal Angles.

As UP is the Angle Bisector of Angle U, It Divides Angle U into two Equal Parts they are Angle(1) and Angle(2)

⇒ Angle(1) = Angle(2)

Given Angle(1) = 5x + 10 and Angle(2) = 3x + 14

⇒ 5x + 10 = 3x + 14

⇒ 2x = 4

⇒ x = 2

⇒ Angle(1) = 5x + 10 = 5(2) + 10 = 10 + 10 = 20

So : Measure of Angle(1) is 20

8 0

3 years ago

John, Sally, and Natalie would all like to save some money. John decides that it

brilliants [131]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) $\$2,700$

Part 5) Is a exponential growth function

Part 6) $A=6,000(1.07)^{t}$

Part 7) $\$11,802.91$

Part 8) $\$6,869.40$

Part 9) Is a exponential growth function

Part 10) $A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

Part 11) $\$13,591.41$

Part 12) $\$6,107.01$

Part 13) Natalie has the most money after 10 years

Part 14) Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

so

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

$10\ years=10(12)=120 months$

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

so

$2\ years=2(12)=24\ months$

For x=24 months

substitute in the linear equation

$y=100(24)+300=\$2,700$

Part 5) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\\ r=7\%=0.07\\n=1$

substitute in the formula above

$A=6,000(1+\frac{0.07}{1})^{1*t}\\ A=6,000(1.07)^{t}$

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{10}=\$11,802.91$

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{2}=\$6,869.40$

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\\r=10\%=0.10$

substitute in the formula above

$A=5,000(e)^{0.10t}$

Applying property of exponents

$A=5,000(1.1052)^{t}$

therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

$A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^{0.10*10}=\$13,591.41$

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

$A=5,000(e)^{0.10*2}=\$6,107.01$

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0

3 years ago

Here's a graph of a linear function. Write the equation that describes that function.

Nataly [62]

Y=1/4x+3 i think is the right answer because your y-intercept is 3 and you go up one and over 4

7 0

3 years ago

Whats the cube root of 3375 by prime factorization

Georgia [21]

Answer:

15

Step-by-step explanation:

Prime factors of 3375 are 3, 3, 3, 5, 5, 5.

Since you need the ∛ of 3375, ∛3375=15

7 0

3 years ago

Read 2 more answers

Family traveled 25 miles in 1/2 hour. If it’s currently 3:00 pm and the destination is 225 miles away, what time will they arriv

dangina [55]

It is currently 03:00 PM, the family will reach at 03:00+4.5 = 07:30 PM

Step-by-step explanation:

We have to calculate the speed first to find the time it will take the family to complete the trip.

Given

Distance = d = 25 miles

Time = t = 1/2 hours = 0.5 hours

$Speed =\frac{d}{t}\\=\frac{25}{0.5}\\=50 miles\ per\ hour$

Now,

Distance remaining = 225 miles

Speed = 50 miles per hour

$s=\frac{d}{t}\\t=\frac{d}{s}\\t=\frac{225}{50}\\t=4.5\ hours$

As we see that the time required to complete the journey is 4.5 hours.

It is currently 03:00 PM, the family will reach at 03:00+4.5 = 07:30 PM

Keywords: Speed, Distance

Learn more about speed at:

#LearnwithBrainly

3 0

3 years ago