Find the components of the vector v with initial point P and terminal point Q. Find the unit vector u in the direction of v.

Mathematics

1 answer:

love history [14]3 years ago

8 0

Answer:

Step-by-step explanation:

v=Q-P

v=(5,1,0)

u=v/(magnitude of v)=(5,1,0)/(\sqrt{5^2+1^2+0^2)

u=(5/5.09,1/5.09,0)

v=Q-P

v=(1,1,0)

u=v/(magnitude of v)=(1,1,0)/(\sqrt{1^2+1^2+0^2)

u=(1/ $\sqrt{2}$ ,1/ $\sqrt{2}$ ,0)

You might be interested in

The number on top of a fraction is called the

olga2289 [7]

The number on top of a fraction is the numerator. The number on the bottom of the fraction is the denominator.

Example : 2/3....the 2 is the numerator and the 3 is the denominator

8 0

4 years ago

First person to answer 10 points

Assoli18 [71]

It’s the third one. Hopefully this helped

8 0

3 years ago

PLEASE HELP 8th GRADE MATH QUESTION OVER HERE!!!

patriot [66]

The side AB measures option 2. $\sqrt{20}}$ units long.

Step-by-step explanation:

Step 1:

The coordinates of the given triangle ABC are A (4, 5), B (2, 1), and C (4, 1).

The sides of the triangle are AB, BC, and CA. We need to determine the length of AB.

To calculate the distance between two points, we use the formula $d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}.$

where ( $x_{1},y_{1}$ ) are the coordinates of the first point and ( $x_{2},y_{2}$ ) are the coordinates of the second point.

Step 2:

For A (4, 5) and B (2, 1), ( $x_{1},y_{1}$ ) = (4, 5) and ( $x_{2},y_{2}$ ) = (2, 1). Substituting these values in the distance formula, we get

$d=\sqrt{\left(2-4\right)^{2}+\left(1-5}\right)^{2}} = \sqrt{\left(2\right)^{2}+\left(4}\right)^{2}}=\sqrt{20}}.$