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eimsori [14]
3 years ago
6

Which of the following ratios would form a proportion with 2/3?

Mathematics
2 answers:
Zolol [24]3 years ago
8 0
B. 6/9 because 6/9 equal to 2/3 so it’s basically the same ratio
dedylja [7]3 years ago
5 0

Answer:

c

Step-by-step explanation:

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The Booster Club has a goal of raising at least $600. The Club has already raised $50. The Booster Club is sponsoring a pancake
mojhsa [17]

Answer:add it up

Step-by-step explanation:then divide them all

8 0
3 years ago
In the Kite Club, there are a total of 23 kids. There are 7 more girls than boys. Write two equations below to represent the sit
Iteru [2.4K]

Answer:

b + b + 7 = 23

2b + 7 = 23

Step-by-step explanation:

b = girls

b + 7 = boys

4 0
3 years ago
Read 2 more answers
6. (5 points) What is 3loga + logb − logc written as a single logarithm?
Jobisdone [24]

Answer: log(\frac{a^3b}{c})

Step-by-step explanation:

You need to use the following Properties of Logarithms:

1)m*log(a)=log(a)^m\\\\2)log(a)+log(b)=log(ab)\\\\3)log(a)-log(b)=log(\frac{a}{b})

Given the following expression:

3log(a) + log(b) - log(c)

You can follow these steps in order to write it as a single logarightm:

- Apply the first property shown above:

=log(a)^3 + log(b) - log(c)

- Apply the second property:

=log(a^3b)- log(c)

- Finally, apply the third property:

=log(\frac{a^3b}{c})

4 0
3 years ago
3x^2-5x-7 find the sum and product​
Bad White [126]

Answer:

s =  \frac{5}{3}

p =  \frac{7}{3}

Step-by-step explanation:

for this equation

a=3

b= -5

c = -7

The sum of equal to

-  \frac{b}{a}

and the product is equal to

\frac{c}{a}

. All you do is replace the values. You can prove both of those using the quadratic formula.

3 0
3 years ago
These are the first six terms of a sequence with a = 2:
inn [45]

Answer:

a_{n} = 9a_{n-1}

Step-by-step explanation:

Note there is a common ratio r between consecutive terms of the sequence, that is

r = 18 ÷ 2 = 162 ÷ 18 = 1458 ÷ 162 = 13122 ÷ 1458 = 9

A recursive formula allows a term in the sequence to be found by multiplying the previous term by the common ratio, that is

a_{n} = 9a_{n-1} with a₁ = 2

7 0
3 years ago
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