Answer:
No
Step-by-step explanation:
No. Congruent triangles should also have corresponding congruent side lengths.
something noteworthy, the y-coordinate for each point is the same, 9⅛, that means is a horizontal line, over which the x-coordinates are at, so since it's a horizontal line, all we need to do is find, what's the distance between 
of course, let's firstly convert the mixed fraction to improper fraction and then check their difference.
![\bf \stackrel{mixed}{5\frac{7}{10}}\implies \cfrac{5\cdot 10+7}{10}\implies \stackrel{improper}{\cfrac{57}{10}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{2}{5}-\left[-\cfrac{57}{10} \right]\implies \cfrac{2}{5}+\cfrac{57}{10}\implies \stackrel{\textit{using the LCD of 10}}{\cfrac{(2)2+(1)57}{10}}\implies \cfrac{4+57}{10}\implies \cfrac{61}{10}\implies 6\frac{1}{10}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B5%5Cfrac%7B7%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B5%5Ccdot%2010%2B7%7D%7B10%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B57%7D%7B10%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B2%7D%7B5%7D-%5Cleft%5B-%5Ccfrac%7B57%7D%7B10%7D%20%5Cright%5D%5Cimplies%20%5Ccfrac%7B2%7D%7B5%7D%2B%5Ccfrac%7B57%7D%7B10%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%2010%7D%7D%7B%5Ccfrac%7B%282%292%2B%281%2957%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B4%2B57%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B61%7D%7B10%7D%5Cimplies%206%5Cfrac%7B1%7D%7B10%7D)
X = 180 - 150 = 30°
z = 180 - 100 = 80°
y = 180 - 30 - 80 = 70°
Answer: x = 30, y = 70, z = 80