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Sindrei [870]
3 years ago
9

Please I need some help

Mathematics
1 answer:
gulaghasi [49]3 years ago
5 0
Id day B. 2.2 kilometers, but its just an estimate
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Find the x- and y- intercepts of the line with the given equation <br><br> -6x+8y=-36
Likurg_2 [28]

Answer:

Y int at

(

0

,

3

2

)

X int at

(

3

,

0

)

Step-by-step explanation:

The line is easier to visualize when the equation is in slope-intercept form:

4

x

+

8

y

=

12

Divide each side by 4:

x

+

2

y

=

3

2

y

=

−

x

+

3

y

=

−

1

2

x

+

3

2

Y-intercept (plug in 0 for x):

y

=

−

1

2

(

0

)

+

3

2

y

=

3

2

X-intercept (plug in 0 for y):

0

=

−

1

2

x

+

3

2

−

3

2

=

−

1

2

x

x

=

3

5 0
3 years ago
Read 2 more answers
IM STUCK i need help WITH THIS PROBLEM THE NUMBER 4 will give brainly
exis [7]

Answer:

Ok say your social life is on that scale, Now the moment you walk into school your life is A which means it hasn't made it anywhere..now as you progress your love life goes up and becomes a B soon you grow popular and hit C as your results sky rocket..suddenly something you do affects that maybe a bad grade or something you did to someone then your social life drops dramatically to a D and soon crumbling to an E.

~ Zachary Mark brainliest if you want Thanks <3 Have a nice day!!!

8 0
3 years ago
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Determine the value of x
maxonik [38]

Answer:

6\sqrt{3}

Step-by-step explanation:

using the sine rule,

\frac{sin 60}{x} = \frac{sin 30}{6} \\x=\frac{sin60 * 6 }{sin30} \\x=6\sqrt{3}

7 0
2 years ago
Find the value of x in the triangle shown below 4 9
Korolek [52]
Where is the triangle?
3 0
2 years ago
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A plane traveled 460 mph with the wind and 400 mph against the wind. Find the speed of the plane in still air and the speed of t
Fudgin [204]
Let's say the speed of the plane is "p", and the speed of the wind is "w".

when the plane goes with the wind, is not really going "p" mph fast, is really going "p + w" mph fast, because the wind is adding speed to it.

likewise when the plane is going against the wind, is also not going "p" fast is going "p - w" mph fast.  Therefore,

\bf \begin{cases}&#10;p+w=460\implies \boxed{w}=460-p \\&#10;p-w=400\\&#10;----------\\&#10;p-\left( \boxed{460 - p} \right)=400&#10;\end{cases}&#10;\\\\\\&#10;2p-460=400\implies 2p=860\implies p=\cfrac{860}{2}\implies p=430
7 0
3 years ago
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