a+2a=3a
3a=3a
The answer is infinetly many solutions.
Answer:
4
Step-by-step explanation:
set
constrain:
Partial derivatives:
Lagrange multiplier:
![\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5Cend%7Barray%7D%5Cright%5D%3Da%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2x%5C%5C2y%5Cend%7Barray%7D%5Cright%5D%2Bb%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3x%5E2%5C%5C3y%5E2%5Cend%7Barray%7D%5Cright%5D)
4 equations:
By solving:
Second mathod:
Solve for x^2+y^2 = 7, x^3+y^3=10 first:
The maximum is 4
Answer:
10.75
Step-by-step explanation:
The cost of an adult ticket is £6 more than that of a child ticket, so will be shown by c+6.
Now, we are told that the cost of four child tickets and two adult tickets is £40.50, so we can put this in an equation and solve for c:
(c+6)+(c+6)+c+c+c+c=40.50
6c+12=40.50
6c=28.50
c=4.75
so, a childs ticket is 4.75
now to find the cost of an adult ticket you add 6,
4.75 + 6
= 10.75
6: 1,3,2,6
7: 1,7
Factors of 6 are 1,3,2,6 because 1x6 (6x1) and 3x2. (2x3)
Factors of 7 are 1,7 because seven is a odd number so you can only multiply it by one and itself. (1x7 or 7x1)
Answer:
c I just saw ur question sorry if I too late
