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3 years ago

BIG POINTS PLEASE HELP ME I'll give braliest

1 answer:

4 0

Irrational kind of means something can't be dealt with, for example, you cannot divide irrational numbers. Rational is something that you can do and will be good to work with, you can divide rational numbers.

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if α,β are the roots of the equation x^{2}-3x+2=0 form an equation whose roots are (α+β)² & (α-β)²

GuDViN [60]

Solution:-

Let's find roots of x² - 3x + 2

=> x² - 3x + 2 = 0.

=> x² - x - 2x + 2 = 0.

=> x ( x - 1 ) -2 ( x - 1) = 0.

=> ( x - 1 ) ( x - 2 ) = 0.

=> x = 2, 1.

Now

( a + ß )² = (2+1)²=3²=9
( a - ß )² = ( 2 - 1 )² = 1² = 1.

So , equⁿ would be ,

=> x² - ( 9 + 1)x + 9×1=0.

=> x² - 10x + 9=0.

6 0

2 years ago

Each week Charlene uses 3/4 of a bag of cat food to feed her cats. She has 112 bags of cat food in stock. How long will her stoc

inessss [21]

The stock of cat food will last for 149 weeks.

Step-by-step explanation:

Given,

Bags of cat food in stock = 112

Bags used each week = $\frac{3}{4}\ of\ one\ bag$

Let,

x be the number of weeks.

Therefore,

$\frac{3}{4}x=112$

Multiplying both sides by 4/3

$\frac{4}{3}*\frac{3}{4}x=112*\frac{4}{3}\\x=\frac{448}{3}\\x=149.33$

Rounding off to nearest whole number;

x=149

The stock of cat food will last for 149 weeks.

Keywords: fraction, multiplication

Learn more about fractions at:

#LearnwithBrainly

4 0

3 years ago

For most answers, you will simply enter your numeric answer directly into the space provided to the right of the equal sign. Ans

Vedmedyk [2.9K]

Answer:

12 dozens of eggs I believe

Step-by-step explanation:

12 eggs are in one dozen

Divide 144 by 12. 144÷12=12

4 0

3 years ago

20 points

g100num [7]

Answer:

the answer is 7/12 hours

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

There are 20 machines in a factory. 7 of the machines are defective.

adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

4 0

3 years ago