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Solnce55 [7]
3 years ago
10

Help me pleaseeee it’s algebra 2

Mathematics
1 answer:
aivan3 [116]3 years ago
4 0
The answer is yes. I already answered this lol
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Determine which postulate or theorem can be used to prove that
EleoNora [17]

Answer:

\triangle ABC \cong \triangle DCB by <u>AAS</u>

Step-by-step explanation:

According to the following two triangles, \triangle ABC and \triangle DCB are congruent by <u>Angle-Angle-Side</u> (AAS), because there are two angles shown and share a side, which is in the middle between triangles.

7 0
3 years ago
You started this year with $458 saved and
vovangra [49]

Answer:

s = 14m + 458

Step-by-step explanation:

current amount = 458

14 per month

s = 14m + 458

6 0
1 year ago
Read 2 more answers
A rectangle is divided into same size squares one row covers 1/8 of the whole rectangle there are 3 squares in each row how many
____ [38]

Answer:

it is one square

Step-by-step explanation:

in the middle is room for one but anywhere else isn't

8 0
3 years ago
plz hurry!! A person standing close to the edge on top of a 108-foot building throws a ball vertically upward. The quadratic fun
Archy [21]

Answer:

The maximum height of the ball is 380.25 feet in the air.

Step-by-step explanation:

The quadratic function:

h(t)=-16t^2+132t+108

Models the ball's height <em>h(t)</em>, in feet, above the ground <em>t</em> seconds after it was thrown.

We want to determine the maximum height of the ball.

Note that this is a quadratic function. Therefore, the maximum or minimum value will always occur at its vertex point.

Since our leading coefficient is leading, we have a maximum point. So to find the maximum height, we will find the vertex. The vertex of a quadratic equation is given by:

\displaystyle \left(-\frac{b}{2a},f\left(\frac{b}{2a}\right)\right)

In this case, <em>a</em> = -16, <em>b</em> = 132, and <em>c</em> = 108. Find the <em>t-</em>coordinate of the vertex:

\displaystyle t=-\frac{132}{2(-16)}=-\frac{132}{-32}=\frac{33}{8}=4.125

So, the maximum height occurs after 4.125 seconds of the ball being thrown.

To find the maximum height, substitute this value back into the equation. Thus:

h(4.125)=-16(4.125)^2+132(4.125)+108=380.25\text{ feet}

The maximum height of the ball is 380.25 feet in the air.

5 0
3 years ago
Which is the answer?
Tom [10]

Answer:

y=3x

Step-by-step explanation:

y=3x is the one according to values in the table

8 0
3 years ago
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