What is 7/9 divided by 1/3???????

Mathematics

1 answer:

tamaranim1 [39]3 years ago

6 0

Answer:

0.259...

Step-by-step explanation:

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While traveling across flat land, you notice a mountain directly in front of you. The angle of elevation to the peak is 1.5°. Af

labwork [276]

Answer:

0.68 miles

Step-by-step explanation:

Let's say that the height of the mountain is h

The distance between the mountain and the car, after moving 23 miles closer to the mountain, will be x (let's pose it as x for now)

tan(1.5°) = opposite/adjacent = h/23 + a

=> h = (23 + a)tan(1.5°) ---- (1)

tan(13°) = h/a

=> h = a(tan(13°)) ---- (2)

Now since h is common among the two equations, we can equate them;

$\left(23+a\right)\tan \left(1.5^{\circ \:}\right)=a\left(\tan \left(13^{\circ \:}\right)\right),\\23\tan \left(1.5^{\circ \:}\right)+\tan \left(1.5^{\circ \:}\right)a=\tan \left(13^{\circ \:}\right)a,\\\\\tan \left(1.5^{\circ \:}\right)a-\tan \left(13^{\circ \:}\right)a=-23\tan \left(1.5^{\circ \:}\right),\\\left(\tan \left(1.5^{\circ \:}\right)-\tan \left(13^{\circ \:}\right)\right)a=-23\tan \left(1.5^{\circ \:}\right),\\\\$

$a=\frac{23\tan \left(1.5^{\circ \:}\right)}{\tan \left(13^{\circ \:}\right)-\tan \left(1.5^{\circ \:}\right)} = 2.94249...$

$h = 2.94249tan\left(13^{\circ }\right) = 0.67932\dots$

The height of the mountain ≈ 0.68 miles

6 0

2 years ago

Can anyone answer this ?

bagirrra123 [75]

$(3 {x}^{2} - 4x - 1) + (8 {x}^{2} - x + 6) \\ \\ combining \: the \: like \: terms,\:we\:have\\ \\ = 3 {x}^{2} + 8 {x}^{2} - 4x - x - 1 + 6 \\ \\ = 11 {x}^{2} - 5x + 5$

$(6 {x}^{2} - x - 4) + ( 2{x}^{2} + 5x - 5) \\ \\combining \: the \: like \: terms, \: we \: have \\ \\= 6 {x}^{2} + 2 {x}^{2} - x + 5x - 4 - 5 \\ \\= 8 {x}^{2} + 4x - 9$

$(4 {x}^{2} + 2x - 5) + (6 {x}^{2} - x - 5) \\ \\ combining \: th e\:l ike \: terms, \: we \: have \\ \\= 4 {x}^{2} + 6 {x}^{2} + 2x - x - 5 - 5 \\ \\= 10 {x}^{2} +x - 10$